05-09-2006
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
With the if statement:
if
How can I make it so it accepts a wildcard after the ${CURR_DAY_MONTH} variable?
Putting
a -f /webtrends/SUN/mrw2/access.${CURR_DAY_DAY}${CURR_DAY_MONTH}*
won't work, right? I think I need some kind of special character so it knows the wildcard is... (3 Replies)
Discussion started by: LordJezo
3 Replies
2. Shell Programming and Scripting
I am just wondering if it's possible to refer to variables within a sed statement as follows:-
cat $file | sed -e 1's/$oldtext/$newtext/' > $file
as when I run the script, the variables are not recognised and nothing happens..??
Thanks (5 Replies)
Discussion started by: sirtrancealot
5 Replies
3. Shell Programming and Scripting
Ok, So up front I'm going to say that I'm a very elementary scripter, and I tend to use tools I don't fully understand, but I shotgun at something until I can get it to work...that said, I can't for the life of me understand why I can't get this to go down the way I want it to.
The goal:
-to... (6 Replies)
Discussion started by: DeCoTwc
6 Replies
4. Shell Programming and Scripting
meas is a shell variable, and this works perfectly fine for me:
awk -v var=$meas -F, '$1==var' /abcd/efgh.txt > temp1.csv
However, i want to introduce another shell variable, named, defnfile in the statement, in place of hardcoded path for efgh.txt like:
awk -v var=$meas -F, '$1==var'... (3 Replies)
Discussion started by: indianjassi
3 Replies
5. Shell Programming and Scripting
is it possible to call a variable in a case statement, for example
lsmonth=Jan|Feb
l |while read ans
do
mymonth=`echo $ans |awk '{print $6}'`
case $mymonth in
$lsmonth) echo do something
;;
*) echo do something else
;;
esac
done
I want to use $lsmonth... (8 Replies)
Discussion started by: gefa
8 Replies
6. Shell Programming and Scripting
kindly find below:-
var="'(]\\{}\$\""
echo $var # it wil give this '(]\{}$"
echo "$var" # '(]\{}$" Doesn't make a difference why???.
if we set IFS to '\' also the below happens
IFS='\'
echo $var # '(] {}$" \ converted to space. Why? weird!!
echo "$var"... (3 Replies)
Discussion started by: ahmad.diab
3 Replies
7. UNIX for Dummies Questions & Answers
HI,
I have 5 variables var1, var2, var3, var4 and var5
I need to initialize all of them to zero.
Is there a way to do it in a single line
something like this
var1=var2=var3=var4=var5=0.
I am unable to achieve this.
What is going wrong? (2 Replies)
Discussion started by: paku
2 Replies
8. UNIX for Dummies Questions & Answers
Hi,
i can print 2nd, 4th and 6th columns in a file using the shell command:
awk -F "|" '{print $2 $4 $6}' file1.txt
Now, the position and number of columns can be variable and from a variable POSLIST
So let's say
POSLIST='$2 $4 $6'
when i use the command:
a)
awk -F "|" '{print... (2 Replies)
Discussion started by: ysrini
2 Replies
9. Shell Programming and Scripting
#!/bin/bash
#timetest
TIMENOW="$(date)"
T1=12:00:00
echo $TIMENOW >timenow
cat timenow |cut -f4 -d' ' >time1
T2=$(sed -n "${1}p" time1)
echo "T1 = " $T1
echo "T2 = " $T2
if then
echo $T1
else
echo $T2
fi
I thought scripting was simple! So why does this script result in:
T1 =... (4 Replies)
Discussion started by: habuchas
4 Replies
10. Shell Programming and Scripting
Environment:
BASH version: GNU bash, version 3.2.51(1)-release (sparc-sun-solaris2.10)
Copyright (C) 2007 Free Software Foundation, Inc.
OS: Oracle Solaris 10 9/10 s10s_u9wos_14a SPARC
Copyright (c) 2010, Oracle and/or its affiliates. All rights reserved.
... (4 Replies)
Discussion started by: os2mac
4 Replies
LEARN ABOUT CENTOS
lreplace
lreplace(n) Tcl Built-In Commands lreplace(n)
__________________________________________________________________________________________________________________________________________________
NAME
lreplace - Replace elements in a list with new elements
SYNOPSIS
lreplace list first last ?element element ...?
_________________________________________________________________
DESCRIPTION
lreplace returns a new list formed by replacing one or more elements of list with the element arguments. first and last are index values |
specifying the first and last elements of the range to replace. The index values first and last are interpreted the same as index values |
for the command string index, supporting simple index arithmetic and indices relative to the end of the list. 0 refers to the first ele- |
ment of the list, and end refers to the last element of the list. If list is empty, then first and last are ignored.
If first is less than zero, it is considered to refer to before the first element of the list. For non-empty lists, the element indicated
by first must exist or first must indicate before the start of the list.
If last is less than first, then any specified elements will be inserted into the list at the point specified by first with no elements
being deleted.
The element arguments specify zero or more new arguments to be added to the list in place of those that were deleted. Each element argu-
ment will become a separate element of the list. If no element arguments are specified, then the elements between first and last are sim-
ply deleted. If list is empty, any element arguments are added to the end of the list.
EXAMPLES
Replacing an element of a list with another:
% lreplace {a b c d e} 1 1 foo
a foo c d e
Replacing two elements of a list with three:
% lreplace {a b c d e} 1 2 three more elements
a three more elements d e
Deleting the last element from a list in a variable:
% set var {a b c d e}
a b c d e
% set var [lreplace $var end end]
a b c d
A procedure to delete a given element from a list:
proc lremove {listVariable value} {
upvar 1 $listVariable var
set idx [lsearch -exact $var $value]
set var [lreplace $var $idx $idx]
}
SEE ALSO
list(n), lappend(n), lindex(n), linsert(n), llength(n), lsearch(n), lset(n), lrange(n), lsort(n), string(n) |
KEYWORDS
element, list, replace
Tcl 7.4 lreplace(n)