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Top Forums UNIX for Dummies Questions & Answers starting processes with timeout? Post 302072748 by jim mcnamara on Saturday 6th of May 2006 12:17:39 AM
Old 05-06-2006
The problem is: on a busy system the pid may possibly be another process. You would in trouble if that process were a process you owned. So, try to keep the sleep value reasonably close to what your process actually needs to complete its job.
 

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LOCK(1) 						    BSD General Commands Manual 						   LOCK(1)

NAME
lock -- reserve a terminal SYNOPSIS
lock [-npv] [-t timeout] DESCRIPTION
The lock utility requests a password from the user, reads it again for verification and then will normally not relinquish the terminal until the password is repeated. There are two other conditions under which it will terminate: it will timeout after some interval of time and it may be killed by someone with the appropriate permission. The following options are available: -n Do not use a timeout value. Terminal will be locked forever. -p A password is not requested, instead the user's current login password is used. -t timeout The time limit (default 15 minutes) is changed to timeout minutes. -v Disable switching virtual terminals while this terminal is locked. This option is implemented in a way similar to the -S option of vidcontrol(1), and thus has the same restrictions. It is only available if the terminal in question is a syscons(4) or vt(4) virtual terminal. SEE ALSO
vidcontrol(1), syscons(4), vt(4) HISTORY
The lock command appeared in 3.0BSD. BSD
July 10, 2002 BSD
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