04-26-2002
/etc/group and umask
__________________________
An easy way to solve this is to add the users who will share these files to the group that it application user is a member of.
If the default group is oracle, then make all the users a member of the group oracle in /etc/group...
IF you want everyone to have permissions in the poppa dir, give them a secondary group of momma in /etc/group.
Also, make sure the group rights are such that users can read/write files in the specified dir.
___________________________
Umask can be modified in the .profile of the specified user. It i will give the opposite of what you set the umask to for new files and dirs created by that user...
If you set "umask 022" then the new file parms will be 644. Note that you cannot give executable permissions with umask. It will not do it even if you give umask 000...
Set umask 006, this will give you 660 for new file creation.
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
Is there a command or shell script which can be used for Finding all files created by a specified userid in a directory and its subdirectories.
Say, I want to find all such files in directory /abc as well as in all the subdirectories such as /abc/xyz or /abc/xyz/pqr aqnd so on which was created... (5 Replies)
Discussion started by: abhilashnair
5 Replies
2. UNIX for Dummies Questions & Answers
Whenever I create a new file the group name is "dnn" and the file permissions are "-rw-r--r--".
How do I get it so when I create files (with vi or other programs) that the default group is "sss" and the permissions are 770?
(I am running HP-UNIX)
Thanks,
GoldFish (2 Replies)
Discussion started by: goldfish
2 Replies
3. UNIX for Advanced & Expert Users
Hi,
Within a SQL file i am calling 5 shell scripts in back ground and redirecting their outputs to different log files in a specific directory.
Now when I observed is, the log files are created with different permissions even though i did not do any thing specific.
For example in... (2 Replies)
Discussion started by: steria_learner
2 Replies
4. Shell Programming and Scripting
Dear All,
I want a Hp Ux command to find out the files created today in a particular directory or mountpoint.
Kindly help.
Thanks
Bhaskar (10 Replies)
Discussion started by: sudiptabhaskar
10 Replies
5. UNIX for Advanced & Expert Users
I have a directory on a Solaris box that has 58 files written to it every 15min. They have a non standard date as part of the file name but always have another name with it. I need to check that directory for files created within the last 15min and then port the results to a log file. There are... (5 Replies)
Discussion started by: jlaigo2
5 Replies
6. Red Hat
Hello All,
I have an application that creates the log files and they created with 600 permissions instead of 644(default). How can I set the permissions so that files can be created with 644. I looked into the /etc/profile for the umask settings and it is set 002(if UID>199). And when I type... (5 Replies)
Discussion started by: s_linux
5 Replies
7. UNIX for Dummies Questions & Answers
Hi,
My apologies if my query is already available on this forum but I am new and could not find.
I need a script to list all directories/sub directories and files with permissions/groups/owners. The script would run from home directory and should capture every directory. How do I do this?
... (4 Replies)
Discussion started by: 8709711
4 Replies
8. Shell Programming and Scripting
Hi all,
i have a folder, with tons of files containing as following,
on /my/folder/jobs/
some_name_2016-01-17-22-38-58_some name_0_0.zip.done
some_name_2016-01-17-22-40-30_some name_0_0.zip.done
some_name_2016-01-17-22-48-50_some name_0_0.zip.done
and these can be lots of similar files,... (6 Replies)
Discussion started by: charli1
6 Replies
9. UNIX for Beginners Questions & Answers
Asking about the permission inherit from the parent directory
I am running the web app with tomcat8, I did use umask 007 to set permission for folder which enable the sub files and folder inherit the permission from the parent directory, I was successful which some directories but the directories... (1 Reply)
Discussion started by: janecaongoc
1 Replies
10. UNIX for Beginners Questions & Answers
Asking about the permission inherit from the parent directory
I am running the web app with tomcat8, I did use umask 007 to set permission for folder which enable the sub files and folder inherit the permission from the parent directory, I was successful which some directories but the directories... (2 Replies)
Discussion started by: janecaongoc
2 Replies
LEARN ABOUT SUSE
pam_umask
PAM_UMASK(8) Linux-PAM Manual PAM_UMASK(8)
NAME
pam_umask - PAM module to set the file mode creation mask
SYNOPSIS
pam_umask.so [debug] [silent] [usergroups] [umask=mask]
DESCRIPTION
pam_umask is a PAM module to set the file mode creation mask of the current environment. The umask affects the default permissions assigned
to newly created files.
The PAM module tries to get the umask value from the following places in the following order:
o umask= argument
o umask= entry of the users GECOS field
o pri= entry of the users GECOS field
o ulimit= entry of the users GECOS field
o UMASK= entry from /etc/default/login
o UMASK entry from /etc/login.defs
OPTIONS
debug
Print debug information.
silent
Don't print informative messages.
usergroups
If the user is not root, and the user ID is equal to the group ID, and the username is the same as primary group name, the umask group
bits are set to be the same as owner bits (examples: 022 -> 002, 077 -> 007).
umask=mask
Sets the calling process's file mode creation mask (umask) to mask & 0777. The value is interpreted as Octal.
MODULE TYPES PROVIDED
Only the session type is provided.
RETURN VALUES
PAM_SUCCESS
The new umask was set successfully.
PAM_SERVICE_ERR
No username was given.
PAM_USER_UNKNOWN
User not known.
EXAMPLES
Add the following line to /etc/pam.d/login to set the user specific umask at login:
session optional pam_umask.so umask=0022
SEE ALSO
pam.conf(5), pam.d(5), pam(8)
AUTHOR
pam_umask was written by Thorsten Kukuk <kukuk@thkukuk.de>.
Linux-PAM Manual 04/01/2010 PAM_UMASK(8)