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Full Discussion: $? variable
Top Forums UNIX for Dummies Questions & Answers $? variable Post 1922 by Neo on Thursday 5th of April 2001 07:59:16 PM
Old 04-05-2001
$? contains the exit code of the last shell command issued. As I recall, it is usually 0 when the execution has no errors and non-zero upon errors (hopefully that's not backward). Example:

Quote:
#echo "hi"
hi
#echo $?
0
Quote:
$dlfjdlkfdjklfd
dlfjdlkfdjklfd: not found
#echo $?
1
 

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args(1) 							   GNU Telephony							   args(1)

NAME
args - manipulate and output command arguments. SYNOPSIS
args [options] args... DESCRIPTION
This command is used to manipulate and echo command line arguments to standard out. This can include adding quotes around each argument passed or a separator, or to output each argument on a separate line. The program source also offers a basic example of how to use shell argument parsing and localization in ucommon. OPTIONS
--delim=char Set a deliminator character, such as ',', to use between each argument when outputing arguments. --directory If argument is a directory, list directory contents as arguments. --follow If argument is a directory and a symlink, follow symlinks recursively. --lines Output each argument on a separate line. --quote=char|pair Set a quote or special leading and trailing pair of characters to surround each argument with when output. A typical use might be --quote=() to surround arguments in parenthesis. --recursive If argument is a directory, recursively scan directory and any subdirectory contents as arguments. --reverse Reverse order of arguments. --help Outputs help screen for the user. AUTHOR
args was written by David Sugar <dyfet@gnutelephony.org>. REPORTING BUGS
Report bugs to bug-commoncpp@gnu.org. COPYRIGHT
Copyright (C) 2009 David Sugar, Tycho Softworks. This is free software; see the source for copying conditions. There is NO warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICU- LAR PURPOSE. GNU uCommon January 2010 args(1)
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