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Full Discussion: Date Substraction
Top Forums UNIX for Dummies Questions & Answers Date Substraction Post 1739 by mib on Wednesday 28th of March 2001 04:54:51 AM
Old 03-28-2001
Code:
#!/bin/bash

# figure out what yesterday was.
date '+%Y %m %d' |
 {
 read year month day

 day=`expr "$day" - 1`
 case "$day" in
 0)
 month=`expr "$month" - 1`
 case "$month" in
 0)
 month=12
 year=`expr "$year" - 1`
 ;;
 esac

 day=`cal $month $year | grep . | fmt -1 | tail -1`
 esac

 echo "Yeseterday was: $day $month $year"
                 }

Last edited by Yogesh Sawant; 05-20-2010 at 10:53 AM.. Reason: added code tags
 

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LEARN ABOUT PHP

cal_to_jd

CAL_TO_JD(3)								 1							      CAL_TO_JD(3)

cal_to_jd - Converts from a supported calendar to Julian Day Count

SYNOPSIS

       int cal_to_jd (int  $calendar, int  $month, int	$day, int  $year)

DESCRIPTION

       cal_to_jd(3)  calculates  the  Julian  day count for a date in the specified $calendar. Supported $calendars are CAL_GREGORIAN, CAL_JULIAN,
       CAL_JEWISH and CAL_FRENCH.

PARAMETERS

	      o $calendar
		- Calendar to convert from, one of CAL_GREGORIAN, CAL_JULIAN, CAL_JEWISH or CAL_FRENCH.

	      o $month
		- The month as a number, the valid range depends on the $calendar

	      o $day
		- The day as a number, the valid range depends on the $calendar

	      o $year
		- The year as a number, the valid range depends on the $calendar

RETURN VALUES

	A Julian Day number.

SEE ALSO

       cal_from_jd(3), frenchtojd(3), gregoriantojd(3), jewishtojd(3), juliantojd(3), unixtojd(3).

PHP Documentation Group 													      CAL_TO_JD(3)
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