03-07-2002
display "*"
Hi,
I've a problem with display "*" character:
I'd like to use a script which take a complete path of set of files or directories in argument and separate them into their "dirname" part and their "basename" part.
It works nearly exept that if i want to display the result (dirname + basename), i have problem while displaying the value of the basename part:
for example with arg="/app/share/*" and argbase=$(basename $arg)
echo $argbase will display all the file and directories instead of "*"
At command prompt, i've no problems but only when using kshell scripts ...
Thanks for your help.
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LEARN ABOUT REDHAT
dirname
DIRNAME(3) Linux Programmer's Manual DIRNAME(3)
NAME
dirname, basename - Parse pathname components
SYNOPSIS
#include <libgen.h>
char *dirname(char *path);
char *basename(char *path);
DESCRIPTION
The functions dirname and basename break a null-terminated pathname string into directory and filename components. In the usual case,
dirname returns the string up to, but not including, the final '/', and basename returns the component following the final '/'. Trailing
'/' characters are not counted as part of the pathname.
If path does not contain a slash, dirname returns the string "." while basename returns a copy of path. If path is the string "/", then
both dirname and basename return the string "/". If path is a NULL pointer or points to an empty string, then both dirname and basename
return the string ".".
Concatenating the string returned by dirname, a "/", and the string returned by basename yields a complete pathname.
Both dirname and basename may modify the contents of path, so if you need to preserve the pathname string, copies should be passed to these
functions. Furthermore, dirname and basename may return pointers to statically allocated memory which may be overwritten by subsequent
calls.
The following list of examples (taken from SUSv2) shows the strings returned by dirname and basename for different paths:
path dirname basename
"/usr/lib" "/usr" "lib"
"/usr/" "/" "usr"
"usr" "." "usr"
"/" "/" "/"
"." "." "."
".." "." ".."
EXAMPLE
char *dirc, *basec, *bname, *dname;
char *path = "/etc/passwd";
dirc = strdup(path);
basec = strdup(path);
dname = dirname(dirc);
bname = basename(basec);
printf("dirname=%s, basename=%s
", dname, bname);
free(dirc);
free(basec);
RETURN VALUE
Both dirname and basename return pointers to null-terminated strings.
BUGS
In versions of glibc up to and including 2.2.1, dirname does not correctly handle pathnames with trailing '/' characters, and generates a
segmentation violation if given a NULL argument.
CONFORMING TO
SUSv2
SEE ALSO
dirname(1), basename(1),
GNU
2000-12-14 DIRNAME(3)