02-11-2002
Reading Particular Line From A File in Unix
Can any u pls tell me :-
I want to read a particular line from a file, say line no. 10.
This can be done by using awk..but that method I think, is inefficient.
Is there any direct command for this?
Thanks
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LEARN ABOUT DEBIAN
synce-pls
PLS(1) http://synce.sourceforge.net/ PLS(1)
NAME
pls - list directory contents
SYNOPSIS
pls [-a] [-R] [-d LEVEL] [-p DEVNAME] [-h] [DIRECTORY]
DESCRIPTION
pls list the contents of a directory on a device connected through SynCE.
Forward slashes ('/') on the command line are converted to backward slashes ('').
File attributes
A Archive
C Compressed
D Directory
H Hidden
I In ROM
M ROM module (can only be executed, not read!)
N Normal
R Read-only
S System
T Temporary
OPTIONS
-d LEVEL
Set debug log level:
0 - No logging (default)
1 - Errors only
2 - Errors and warnings
3 - Everything
-p DEVNAME
Use the device with the given name, instead of the default.
-a Show all files including those marked as hidden.
-R Recursively list subdirectories.
-h Display help message.
DIRECTORY
The full path name to the directory. Wild cards are allowed, but only for the trailing part of the path, and should be protected
from the shell. If this parameter is relative, it is assumed to be relative to the "My Documents" folder. Similarly, if this parame-
ter is omitted, the contents of the "My Documents" folder is listed.
AUTHOR
This manual page was written by David Eriksson <twogood@users.sourceforge.net>.
SEE ALSO
synce(1) pcp(1) pls(1) prm(1) pmkdir(1) prmdir(1)
The SynCE project November 2002 PLS(1)