01-02-2002
variables in sed
when i do something like substituting a particular thing with a system variable, i am unable to do that expect the varible name getting into that.
for ex.. i tried,
sed -e 's/date/`date`/g' <if >of
but i got date replaced with "`date`" and not with the actual date ..
same case happened with a variable $var.
Can I know where I go wrong?
Thanks
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LEARN ABOUT PHP
datetimeinterface.format
DATETIMEINTERFACE.FORMAT(3) 1 DATETIMEINTERFACE.FORMAT(3)
DateTime::format - Returns date formatted according to given format
Object oriented style
SYNOPSIS
public string DateTime::format (string $format)
DESCRIPTION
string DateTimeImmutable::format (string $format) string DateTimeInterface::format (string $format)
Procedural style
string date_format (DateTimeInterface $object, string $format)
Returns date formatted according to given format.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3)
o $format
- Format accepted by date(3).
RETURN VALUES
Returns the formatted date string on success or FALSE on failure.
EXAMPLES
Example #1
DateTimeInterface.format(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
echo $date->format('Y-m-d H:i:s');
?>
Procedural style
<?php
$date = date_create('2000-01-01');
echo date_format($date, 'Y-m-d H:i:s');
?>
The above example will output:
2000-01-01 00:00:00
NOTES
This method does not use locales. All output is in English.
SEE ALSO
date(3).
PHP Documentation Group DATETIMEINTERFACE.FORMAT(3)