12-17-2001
Doubt.
Yes, sizeof return the bytes that the struct allocate in memory but how two struct's with the same description, the diference is only in the order of fields, can have diferent sizes?
How a double and a char[] can have a diferent sizeof a char[] and a double. That's my doubt.
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LEARN ABOUT DEBIAN
offsetof
OFFSETOF(3) Linux Programmer's Manual OFFSETOF(3)
NAME
offsetof - offset of a structure member
SYNOPSIS
#include <stddef.h>
size_t offsetof(type, member);
DESCRIPTION
The macro offsetof() returns the offset of the field member from the start of the structure type.
This macro is useful because the sizes of the fields that compose a structure can vary across implementations, and compilers may insert
different numbers of padding bytes between fields. Consequently, an element's offset is not necessarily given by the sum of the sizes of
the previous elements.
A compiler error will result if member is not aligned to a byte boundary (i.e., it is a bit field).
RETURN VALUE
offsetof() returns the offset of the given member within the given type, in units of bytes.
CONFORMING TO
C89, C99, POSIX.1-2001.
EXAMPLE
On a Linux/i386 system, when compiled using the default gcc(1) options, the program below produces the following output:
$ ./a.out
offsets: i=0; c=4; d=8 a=16
sizeof(struct s)=16
Program source
#include <stddef.h>
#include <stdio.h>
#include <stdlib.h>
int
main(void)
{
struct s {
int i;
char c;
double d;
char a[];
};
/* Output is compiler dependent */
printf("offsets: i=%ld; c=%ld; d=%ld a=%ld
",
(long) offsetof(struct s, i),
(long) offsetof(struct s, c),
(long) offsetof(struct s, d),
(long) offsetof(struct s, a));
printf("sizeof(struct s)=%ld
", (long) sizeof(struct s));
exit(EXIT_SUCCESS);
}
COLOPHON
This page is part of release 3.44 of the Linux man-pages project. A description of the project, and information about reporting bugs, can
be found at http://www.kernel.org/doc/man-pages/.
GNU
2008-07-12 OFFSETOF(3)