02-08-2001
Is there any way to evaluate the function "stepup" and echo/print it out in one statement or are we stuck doing 2 separate statements - one to evaluate the function and another to display it. Is there a way to do it within the function (ie, return)?
Thanks.
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LEARN ABOUT PHP
oci_field_name
OCI_FIELD_NAME(3) OCI_FIELD_NAME(3)
oci_field_name - Returns the name of a field from the statement
SYNOPSIS
string oci_field_name (resource $statement, mixed $field)
DESCRIPTION
Returns the name of the $field.
PARAMETERS
o $statement
- A valid OCI statement identifier.
o $field
- Can be the field's index (1-based) or name.
RETURN VALUES
Returns the name as a string, or FALSE on errors.
EXAMPLES
Example #1
oci_field_name(3) example
<?php
// Create the table with:
// CREATE TABLE mytab (number_col NUMBER, varchar2_col varchar2(1),
// clob_col CLOB, date_col DATE);
$conn = oci_connect("hr", "hrpwd", "localhost/XE");
if (!$conn) {
$m = oci_error();
trigger_error(htmlentities($m['message']), E_USER_ERROR);
}
$stid = oci_parse($conn, "SELECT * FROM mytab");
oci_execute($stid, OCI_DESCRIBE_ONLY); // Use OCI_DESCRIBE_ONLY if not fetching rows
echo "<table border="1">
";
echo "<tr>";
echo "<th>Name</th>";
echo "<th>Type</th>";
echo "<th>Length</th>";
echo "</tr>
";
$ncols = oci_num_fields($stid);
for ($i = 1; $i <= $ncols; $i++) {
$column_name = oci_field_name($stid, $i);
$column_type = oci_field_type($stid, $i);
echo "<tr>";
echo "<td>$column_name</td>";
echo "<td>$column_type</td>";
echo "</tr>
";
}
echo "</table>
";
// Outputs:
// Name Type
// NUMBER_COL NUMBER
// VARCHAR2_COL VARCHAR2
// CLOB_COL CLOB
// DATE_COL DATE
oci_free_statement($stid);
oci_close($conn);
?>
NOTES
Note
In PHP versions before 5.0.0 you must use ocicolumnname(3) instead. This name still can be used, it was left as alias of
oci_field_name(3) for downwards compatability. This, however, is deprecated and not recommended.
SEE ALSO
oci_num_fields(3), oci_field_type(3), oci_field_size(3).
PHP Documentation Group OCI_FIELD_NAME(3)