11-13-2001
I don't want to plagerize so I give credit to Dale Dougherty and Arnold Robins who wrote "sed and awk" which I mentioned in my previous post (you really should buy it). It may not be exactly what you want but should be really close:
#!/bin/sh
ls -sl $* | awk'
#filesum: list files and total size in bytes
#input: long listing produced by "ls -l"
#1 output column headers
BEGIN { print "BYTES", "\t", "FILE" }
#2 test for 9 fields; files begin with "-"
NF == 9 && /^-/ {
sum += $5 # accumulate size of file
++filenum # count number of files
print $5, "\t", $9 # print size and filename
}
#3 Test for 9 fields; directory begins with "d"
NF == 9 && /^d/ {
print "<dir>", "\t", $9 #print <dir> and name>
}
#4 test for ls -lR line .dir:
$1 ~ /^\..*:$/ {
print "\t" $0 #print that line proceeded by a tab
}
#5 once all is done,
END {
#print total file size and number of files
print "Total: ", sum, "bytes (" filenum " files)"
}'
This will count the total number of files and their total combined size. I highly recommend the sed and awk book. I actually carry it in my briefcase all the time because it is just such a good reference book and awk is such a powerfull tool. It is well worth the time to learn the ins and outs of awk.
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hi,
I had this syntax and no matter what I do, I can't get it run.
err message:
run6: syntax error at line 121 : `(' unexpected
I went to line 121 and it's comment out!
All the variables passed to nawk are valid.
There are two places I suspect have the problem:
1.... (3 Replies)
Discussion started by: whatisthis
3 Replies
2. UNIX for Advanced & Expert Users
I found a command who prints x lines before and after a line who contain a searched string in a text file.
The command is :
-------------------
nawk 'c-->0;$0~s{if(b)for(c=b+1;c>1;c--)print r;print;c=a}b{r=$0}' b=2 a=4 s="string" file1
...where "b" and "a" are the number of lines to print... (2 Replies)
Discussion started by: ctap
2 Replies
3. Shell Programming and Scripting
i'm new to shell scripting and have a problem please help me
in the script i have a nawk block which has a variable count
nawk{
.
.
.
count=count+1
print count
}
now i want to access the value of the count variable outside the awk block,like..
s=`expr count / m`
(m is... (5 Replies)
Discussion started by: saniya
5 Replies
4. Shell Programming and Scripting
What am I doing wrong here? I get syntax error.
I am trying to parse a file looking for the lines with "running" as the first field then print the 5th field, then looking at the 9th field for specific values and writing the whole line to a junk file.
nawk ';
{if ($1 == "running")... (10 Replies)
Discussion started by: beppler
10 Replies
5. Shell Programming and Scripting
Hi Gurus,
I am using a script as under :
read string
nawk -v search="$string" '
/a/,/z/ {
block = (block ? block ORS : "") $0;
}
/z/ {
if (block ~ search)
print block;
} ' <File>
nawk -v search="$string" '
/b/,/z/ {
... (1 Reply)
Discussion started by: vanand420
1 Replies
6. Shell Programming and Scripting
hi people;
this is my two awk code:
nawk '/cell+-/{r=(NF==8) ? $4FS$5FS$6 : NF==7 ? $4FS$5 : $4 ;c=split(r,rr);for (i=1;i<=c;i++){if(rr != "111111"){printf($3" %d ""\n",(i+3))}}printf("")}' /home/gc_sw/str.txt > /home/gc_sw/predwn.txt
nawk -F'*' '{gsub(/ *$/,"")}$0=$1$($NF-2)'... (2 Replies)
Discussion started by: gc_sw
2 Replies
7. UNIX for Dummies Questions & Answers
Hi,
Please help me I want to filter all messages having a value less than a particular value..Please advice how to use <= in the below red marked script..
Getting the error as no such file or directory for the marked line no.
Thanks in advance...
Script is as under :
read message
gawk... (5 Replies)
Discussion started by: vanand420
5 Replies
8. Shell Programming and Scripting
help out with code. two files aaa bbb contains some records..output file xyz should be like this..see below
i/p file:aaa
08350|60521|0000|505|0000|1555|000|NYCMT|Pd_1 |-11878
i/p file: bbb
60521|60510
o/p file :xyz
60510|08350|60521|0000|505|0000|1555|000|NYCMT|Pd_1 |-11878 (5 Replies)
Discussion started by: Diddy
5 Replies
9. Shell Programming and Scripting
hi guys,
I am writing a code and have stuck at one point. Inside nawk I am storing my desired variable a, I just need to find if a is present in an external file error.log or not. If yes, print something. grep or for loop not working properly inside nawk. Sample code provided.
nawk '
BEGIN... (5 Replies)
Discussion started by: shekhar2010us
5 Replies
10. Shell Programming and Scripting
Hi.. i am running nawk scripts on solaris system to get records of file1 not in file2 and find duplicate records in a while with the following scripts -compare
nawk 'NR==FNR{a++;next;} !a {print"line"FNR $0}' file1 file2duplicate - nawk '{a++}END{for(i in a){if(a-1)print i,a}}' file1in the middle... (12 Replies)
Discussion started by: Abhiraj Singh
12 Replies
LEARN ABOUT CENTOS
abrt-dump-oops
ABRT-DUMP-OOPS(1) ABRT Manual ABRT-DUMP-OOPS(1)
NAME
abrt-dump-oops - Extract oops from FILE (or standard input)
SYNOPSIS
abrt-dump-oops [-vusoxtm] [-d DIR]/[-D] [FILE]
DESCRIPTION
This tool creates problem directory from, updates problem directory with or prints oops extracted from FILE or standard input.
OPTIONS
-v, --verbose
Be more verbose. Can be given multiple times.
-s
Log to syslog
-o
Print found oopses on standard output
-d DIR
Create new problem directory in DIR for every oops found
-D
Same as -d DumpLocation, DumpLocation is specified in abrt.conf
-u PROBLEM
Save the extracted information in PROBLEM directory
-x
Make the problem directory world readable. Usable only with -d/-D
-t
Throttle problem directory creation to 1 per second
-m
Print search string(s) for abrt-watch-log to stdout and exit
SEE ALSO
abrt-watch-log(1), abrt.conf(5)
AUTHORS
o ABRT team
abrt 2.1.11 06/18/2014 ABRT-DUMP-OOPS(1)