Sponsored Content
Full Discussion: Loop not working
Top Forums Shell Programming and Scripting Loop not working Post 10056 by LivinFree on Wednesday 7th of November 2001 01:50:11 AM
Old 11-07-2001
You mention that you already tried looping it...
It didn't work when you did something like this?:

for each in `ls -1 log*`
do
cat $each|awk -F: '$2=="SMTP-Accept" && $5~/@maildomain/ {s=$5;u[s]++;las=substr($1)} END {for (i in u) {print i,u[i],las}}'|sort>>/tmp/mailusage.list
done

What happened when you tried that?
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

if loop is not working

Hello i am trying to remove a line using an input file , but this depends upon user interaction here is the sample #!/bin/sh echo "Please enter whether you want to remove Profile" read value1 if ;then sed /movie/d temp.txt> temp3.txt else echo "Script didnot remove profile" fi ... (3 Replies)
Discussion started by: ranga27
3 Replies

2. Shell Programming and Scripting

For loop not working...! :(

Could some one help me on this... For loop is working...! for x in $i do for y in $j do z=`echo $y | awk '{print $2}'` if then FS=`/usr/bin/echo $y` echo $FS >>$Basic_location/out.csv fi done CPRT="Cpoyright @ BTOIDCIM" done (3 Replies)
Discussion started by: bullz26
3 Replies

3. UNIX for Dummies Questions & Answers

If then else loop not working

If then else segment of below code is not working. For each filename code is displaying output for if part as well as else part. Please help its urgent. for usercusttop in `echo ${filename}|sort|uniq|cut -c 1-${actualwordcount}` do ... (2 Replies)
Discussion started by: findprakash
2 Replies

4. UNIX for Advanced & Expert Users

If loop is not working

The following piece of code is not running because it is fails to go inside the if condition. i want to create a directory if there is no directory in the input path. i am using Linux, by CENT. Please help. echo " Enter the path where you u want to extract the tar" read EXTRACT_PATH ls -ld... (12 Replies)
Discussion started by: toanilsharma1
12 Replies

5. Shell Programming and Scripting

While loop not working

here we go.. While loop is not working file.. It also invokes one more shell scripts for which parameters need to passed on. while read line do #### #### We want to have a logfile for each load #### PLog="${LogDir}/${Script}.log"; #### ... (5 Replies)
Discussion started by: premkumardr
5 Replies

6. Shell Programming and Scripting

while loop not working

hi everyone i am facing a very strange problem . please help me why my while loop is not working. below is my code #!/bin/ksh file=RCMC_ABC_999_080924_210813.DAR echo ${file} value=001 count=10 echo "abc" echo ${count} value=$((${value} + 1 )) echo ${value} while ] do echo... (3 Replies)
Discussion started by: aishsimplesweet
3 Replies

7. Shell Programming and Scripting

For loop not working

Hi All, For loop in ksh not working if it was given in the following method. simple script: for i in {1..4} do echo $i done Output: {1..4} Even below also not working :( Script: for (( c=1; c<=5; c++ )) do echo "Welcome $c times..." done Output: ./x.sh: 0403-057 Syntax error... (13 Replies)
Discussion started by: girish_satyam
13 Replies

8. Programming

C While Loop not working like C++

Hi new to C give me a hand thank. do { bzero(input,256); printf("Please enter the country name!"); scanf("%s",input); //& character is essential for scanf(), %f = float, %399s as the last character to be the null character ('\0'). } while... (5 Replies)
Discussion started by: GQiang
5 Replies

9. UNIX for Dummies Questions & Answers

for loop not working

Hi, I have ten different files to extract. so I thought for loop will help me. but it's not working for me. Please advice what I am doing wrong. for INCI in 1 2 3 4 5 6 7 8 9 10 do tar -xvf Update_INCI11.10.002_lnx86_1of10.tar done second file name is... (3 Replies)
Discussion started by: samnyc
3 Replies

10. Shell Programming and Scripting

For-loop not working

Hello all, I would like to unzip some files with a for-loop. Is there anyone who could tell me how I should do this - in a correct way? for file in $(ls); do echo gzip -d < $file | tar xf -; done The problem is the pipe - I believe. But how could I do it? I need it for the command... (4 Replies)
Discussion started by: API
4 Replies
sort(3perl)						 Perl Programmers Reference Guide					       sort(3perl)

NAME
sort - perl pragma to control sort() behaviour SYNOPSIS
use sort 'stable'; # guarantee stability use sort '_quicksort'; # use a quicksort algorithm use sort '_mergesort'; # use a mergesort algorithm use sort 'defaults'; # revert to default behavior no sort 'stable'; # stability not important use sort '_qsort'; # alias for quicksort my $current; BEGIN { $current = sort::current(); # identify prevailing algorithm } DESCRIPTION
With the "sort" pragma you can control the behaviour of the builtin "sort()" function. In Perl versions 5.6 and earlier the quicksort algorithm was used to implement "sort()", but in Perl 5.8 a mergesort algorithm was also made available, mainly to guarantee worst case O(N log N) behaviour: the worst case of quicksort is O(N**2). In Perl 5.8 and later, quicksort defends against quadratic behaviour by shuffling large arrays before sorting. A stable sort means that for records that compare equal, the original input ordering is preserved. Mergesort is stable, quicksort is not. Stability will matter only if elements that compare equal can be distinguished in some other way. That means that simple numerical and lexical sorts do not profit from stability, since equal elements are indistinguishable. However, with a comparison such as { substr($a, 0, 3) cmp substr($b, 0, 3) } stability might matter because elements that compare equal on the first 3 characters may be distinguished based on subsequent characters. In Perl 5.8 and later, quicksort can be stabilized, but doing so will add overhead, so it should only be done if it matters. The best algorithm depends on many things. On average, mergesort does fewer comparisons than quicksort, so it may be better when complicated comparison routines are used. Mergesort also takes advantage of pre-existing order, so it would be favored for using "sort()" to merge several sorted arrays. On the other hand, quicksort is often faster for small arrays, and on arrays of a few distinct values, repeated many times. You can force the choice of algorithm with this pragma, but this feels heavy-handed, so the subpragmas beginning with a "_" may not persist beyond Perl 5.8. The default algorithm is mergesort, which will be stable even if you do not explicitly demand it. But the stability of the default sort is a side-effect that could change in later versions. If stability is important, be sure to say so with a use sort 'stable'; The "no sort" pragma doesn't forbid what follows, it just leaves the choice open. Thus, after no sort qw(_mergesort stable); a mergesort, which happens to be stable, will be employed anyway. Note that no sort "_quicksort"; no sort "_mergesort"; have exactly the same effect, leaving the choice of sort algorithm open. CAVEATS
As of Perl 5.10, this pragma is lexically scoped and takes effect at compile time. In earlier versions its effect was global and took effect at run-time; the documentation suggested using "eval()" to change the behaviour: { eval 'use sort qw(defaults _quicksort)'; # force quicksort eval 'no sort "stable"'; # stability not wanted print sort::current . " "; @a = sort @b; eval 'use sort "defaults"'; # clean up, for others } { eval 'use sort qw(defaults stable)'; # force stability print sort::current . " "; @c = sort @d; eval 'use sort "defaults"'; # clean up, for others } Such code no longer has the desired effect, for two reasons. Firstly, the use of "eval()" means that the sorting algorithm is not changed until runtime, by which time it's too late to have any effect. Secondly, "sort::current" is also called at run-time, when in fact the compile-time value of "sort::current" is the one that matters. So now this code would be written: { use sort qw(defaults _quicksort); # force quicksort no sort "stable"; # stability not wanted my $current; BEGIN { $current = print sort::current; } print "$current "; @a = sort @b; # Pragmas go out of scope at the end of the block } { use sort qw(defaults stable); # force stability my $current; BEGIN { $current = print sort::current; } print "$current "; @c = sort @d; } perl v5.14.2 2010-12-30 sort(3perl)
All times are GMT -4. The time now is 12:58 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy