UNIX for Dummies Questions & Answers

Hi All,

I am new to perl and have been trying to write a short script to check a process.Though i havent reached to the stage where i can match the output.
I am trying to pass a variable x with value /opt/RGw/csbp-base/CSBP_BAT.01.00.05/csbp_BAT.01.00.05.jar

and then pass another variable y to check if the process is running in the system

ps -ef | grep -i "csbp_BAT.01.00.05.jar" | grep -v grep |awk -F" " '{print $11}'
Though this command works from the command line.but if i run and print the same via the script i get all messed up

#!/usr/bin/perl
$x="/opt/RGw/csbp-base/CSBP_BAT.01.00.05/csbp_BAT.01.00.05.jar";
$y=`ps -ef | grep -i "csbp_BAT.01.00.05.jar" | grep -v grep |awk -F" " '{print $11}'`;
print "\n";
print "$x \n";
print " \n";
print "$y";
print "\n";
#echo $y;
#if [$x=$y]#then
# echo "1st step completed"
# echo "let me try somemore"
#else
#echo "try again"
#echo "will need to see how it works"
#fi
#exit


Thanks in advance for clearing my doubts.

Br///
pistachio

If you have fuser or lsof on your system coding that is easier than grepping thru ps -ef output....

Code:

perl -e ' if(len("$ARGV[0])> 0) { 
                  print " found\n" 
             } else 
               {print "not found\n"}; \
              "$(lsof -F u /opt/RGw/csbp-base/CSBP_BAT.01.00.05/csbp_BAT.01.00.05.jar 2>/dev/null)"

It's not clear to me what the problem is, though. To compare two strings, use the eq operator. Remember to chomp the output from the backticks, though.

The ps script could really be simplified a lot. Why not code it to only print if the value of $11 is exactly what you want in the first place?

Code:

ps -ef | awk '$11 == "/opt/RGw/csbp-base/CSBP_BAT.01.00.05/csbp_BAT.01.00.05.jar"'