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Grep and extract the characters after

 
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# 1  
Old 07-03-2007
Grep and extract the characters after
Hi All,

I have lines like below in a file

A /u/ab/test1.dat
A/u/ab/test2.dat
A /u/bb/test3.dat
A/u/cc/test4.dat

I will need

/u/ab/test1.dat
/u/ab/test2.dat
/u/bb/test3.dat
/u/cc/test4.dat

Pls help

Thanks
# 2  
Old 07-03-2007
Code:
root@mp-wst01 # cat testfile
A /u/ab/test1.dat
A/u/ab/test2.dat
A /u/bb/test3.dat
A/u/cc/test4.dat
root@mp-wst01 # cut -f"2" -d"A" < testfile | sed 's/ //' > newfile
root@mp-wst01 # cat newfile
/u/ab/test1.dat
/u/ab/test2.dat
/u/bb/test3.dat
/u/cc/test4.dat
root@mp-wst01 #

regards pressy
# 3  
Old 07-03-2007
Code:
awk '{gsub(/^A\ */,"")}{print}' file

# 4  
Old 07-04-2007
I hope that you do not want the first character in your file, so below command would help you

Code:
cut -c2- file > newfile

# 5  
Old 07-04-2007
Code:
sed "s/^A *//" filename

# 6  
Old 07-04-2007
Code:
sed 's/^. *//' filename

# 7  
Old 07-04-2007
Code:
sed 's!^[^/]*!!' filename

 
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