UNIX for Dummies Questions & Answers

hi i have file having following contain

2~%%~2~%%~7~%%~1~%%~none~%%~XYZ_MOV_HDR_REC~%%~1~%%~17_REC_ID == "H"
2~%%~2~%%~8~%%~2~%%~none~%%~XYZ_MOV_EXCL~%%~2~%%~20_UPC<=99999999

see the last column of first line having spaces i have a script

cat rec_iden_file
for i_line in `cat rec_iden_file`
do
echo $i_line
done

here i am printing each line of file
but as first line has a space in last column output of script is

-------------------------------
2~%%~2~%%~7~%%~1~%%~none~%%~XYZ_MOV_HDR_REC~%%~1~%%~17_REC_ID == "H"
2~%%~2~%%~8~%%~2~%%~none~%%~XYZ_MOV_EXCL~%%~2~%%~20_UPC<=99999999
2~%%~2~%%~7~%%~1~%%~none~%%~XYZ_MOV_HDR_REC~%%~1~%%~17_REC_ID
==
"H"
2~%%~2~%%~8~%%~2~%%~none~%%~XYZ_MOV_EXCL~%%~2~%%~20_UPC<=99999999
-------------------------
see the first line treated as 3 lines...

any pointers why this is happening and solution for it

thanks
mahabunta

By default IFS is space. If you want to print the whole line then set IFS to some character that is not in the file

or use this

Code:

cat rec_iden_file
while read i_line
do
echo $i_line
done < rec_iden_file

thanks anubh while loop worked...