UNIX for Dummies Questions & Answers

openssl is a little picky about line length. All lines but the last have to be exactly 64 characters long. The base64 utility is more tolerant. Read more here

Marco,

I'm running out at the moment so can't troubleshoot this for you but a great place to look would be to google "bash loops" (at least for me the first hit has your answer).

Best of luck I know you'll get it!

ok thanks you, i will search and if i don't found nothing you will come to help me ok? thanks you very much bye

The correct syntax for a while loop would be:

Code:

i=0
while (( i++ < 50 ))
do
    # commands go here
done

thanks you very much, and where i put AfB21= ?

Code:

echo AfB21= >> /Users/Supermarco/Desktop/2.txt; done

a script like this:

Code:

i=0
while (( i++ < 50 ))
do
   base64 -d /Users/Supermarco/Desktop/1.txt > /Users/Supermarco/Desktop/2.txt; 
   echo AfB21= >> /Users/Supermarco/Desktop/1.txt; 
done

but it doesn't decrypt it but only write 50 times AfB21= , how i can decode them and after it writes AfB21= ?

I can't see what you are trying to accomplish with this. In a base64 encoded file, characters always show up in groups of four. After decoding they yield three characters of cleartext. Everything else does not work.

The equal sign is also a filler, only allowed at the end of the encoded text, to make sure, the encoded text is a multiple of 4 characters.

Also, overwriting the output file 50 times does not make much sense. If the appending of AfB21= would make sense, you better append it 50 times and then decode once.

Code:

i=0
while (( i++ < 50 ))
do
   base64 -d /Users/Supermarco/Desktop/1.txt > /Users/Supermarco/Desktop/2.txt && echo AfB21= >> /Users/Supermarco/Desktop/1.txt
done

But really not sure what you want...