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Need to exclude certain file extensions while listing the file using ls

 
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# 1  
Old 08-06-2013
Need to exclude certain file extensions while listing the file using ls
Hi friends,
I need to check for the latest file
say i have list of files like this

Code:
test_files
test_files.1
test_files.2
test_files.3.bin.Z

I do it this way

Code:
ls -lrt test_files*|tail -1

Now i need to exclude test_files.3.bin.Z even if it is the latest file,how do i do it?

tried

Code:
ls -lrt test_files*|grep -v *.bin.Z

# 2  
Old 08-06-2013
Hello,

Could you please check the following command.


Code:
ls -ltr | awk '/test_files*/' | grep -v "test_files.[0-9].bin.*" | tail -1


Note: I have make it according to your bin file name.


Thanks,
R. Singh
# 3  
Old 08-06-2013
Thanks it works perfectly. Smilie
# 4  
Old 08-06-2013
That string of pipes after ls can be replaced by one awk cmd:
Code:
ls -t | awk '/test_files*/ && !/bin/ {print; exit}'

---------- Post updated at 16:41 ---------- Previous update was at 16:31 ----------

In a recent bash, you can use "extended pattern matching operators":
Code:
ls -t @(test_!(*.bin.*)) | head -1

Might save a millisecond or two.
 
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