UNIX for Dummies Questions & Answers

How do I create a shell script that would get the current system date in format of yyyymmdd and use that result to concatenate it to a filename that it would look like this: sample20051024.dat

Code:

example
--------
current system date: 24-Oct-2005
filename: sample.dat

when the shell script run it now becomes sample20051024.dat

Thanks.

Did you check the FAQ section? I believe this has been answered there.
https://www.unix.com/answers-to-frequently-asked-questions/

Assuming that you are accepting the system date and the filename from the user, you can use this:

Code:

#!/bin/ksh

oldIFS=$IFS
IFS=$IFS.-
echo "Enter system date: \c"
read year month day
echo "Enter filename: \c"
read fname ext

echo $fname$year$month$day.$ext

IFS=$oldIFS

#!/bin/sh -f
if [ "${1}" = "" ]; then
echo " Usage: $0 <filename>"
exit 1
elif [ ! -e "${1}" ]; then
echo "File ${1} not found"
exit 2
fi

year=`date +%Y`
mon=`date +%m`
mon3=`date +%b`
day=`date +%d`
base=`echo ${1} | cut -d'.' -f1`
suf=`echo ${1} | cut -d'.' -f2`
newfile=${base}${year}${mon}${day}.${suf}

echo "current system date: ${day}-${mon3}-${year}"
echo "filename: ${1}"
echo "new filename: ${newfile}"
mv ${1} ${newfile}

Hi!

Just one tiny comment: you can use one single date command in order to form the filename:

Code:

date "${base}%Y%m%d.${suf}"

Also, echo command does not require sitation marks.

Regards,

pen

thank you all.