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Using printf in bash

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Old Unix and Linux 01-03-2013
lavender lavender is offline
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Using printf in bash


Code:
printf "%5.5\n" "1234567890"

will print 12345 . How do I get it to print
67890
Essentially, I just want the last 5 characters rather than the first 5.

Last edited by Scrutinizer; 01-04-2013 at 06:19 AM..
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Old Unix and Linux 01-03-2013
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Substring Extraction


Code:
num="1234567890"
printf "%d\n" ${num: -5}

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Old Unix and Linux 01-04-2013
RudiC RudiC is offline Forum Staff  
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This works for numbers. Use %s format specifier for characters:
Code:
$ var="ABCDEFGHIJK"
$ printf "%5s\n" ${var:5}
FGHIJK
or
$ printf "%5s\n" ${var: -3}
  IJK

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Old Unix and Linux 01-04-2013
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Code:
num="1234567890"
echo "${num#?????}"

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