UNIX for Dummies Questions & Answers

I have a find command that finds all files in a folder older than 6 days


i.e

find . -name "hourly.*" -mtime + 6

This gives me an output

/oralogs/.snapshot/hourly.0
/oralogs/.snapshot/hourly.1
/oralogs/.snapshot/hourly.2

I would like the output to be

hourly.0
hourly.1
hourly.2

How do I accomplish that

I have to pass the output to -exec rsh command

Help!

Thank you

Neeraj

Don't know about find, but you could pipe an awk command, something like:

find ...stuff | awk -F/ '{print $4}'

that is to say that your data from the find will always be show up like:
/oralogs/.snapshot/hourly.0

and not with +/- a directory, like:
/oralogs/.snapshot/tmp/hourly.0
/oralogs/hourly.0

then you whould have to of course change the awk statement to $5 or $3 etc.

you can use the "basename" (POSIX.2 compatible, i.e FreeBSD, Linux..),...

it's gonna be like this:

$ for i in `find . -name "hourly.*" -mtime + 6`; do echo "This file is: "$i; done

... replace the 'echo "This file is: $i' for the command you expect to run with each file found.

try this:

for i in $(find / -name "hourly.*" -mtime +6|cut -f4 -d'/'); do echo "The files are: "$i; done

Try...

Code:

find . -name "hourly.*" -mtime +6 -exec basename {} \;

Ygor:

Your reply does give me the output I want. But it already uses the exec command in the line and I cannot use the exec command to execute the rsh command I want to. Any more suggestions? Thank you for all your replies.

Neeraj