Extracting rows from a text file based on the values of two columns (given ranges)


 
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Old 10-19-2012
Extracting rows from a text file based on the values of two columns (given ranges)

Hi,

I have a tab delimited text file with multiple columns. The second and third columns include numbers that have not been sorted. I want to extract rows where the second column includes a value between -0.01 and 0.01 (including both numbers) and the first third column includes a value between 1 and 5 (including). How do I go about doing that? Thanks!

Input:
Code:
a -0.01 5
b -0.02 3
c 0 3
d 0.005 6

Output:
Code:
a -0.01 5
c 0 3

 
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pfscut(1)						      General Commands Manual							 pfscut(1)

NAME
pfscut - Extract a rectangle out of a frame in PFS stream SYNOPSIS
pfscut [--left <columns>] [--right <columns>] [--top <rows>] [--bottom <rows>] [--width <new_width>] [--height <new_height>] [--help] [x_ul y_ul x_br y_br] DESCRIPTION
Extract a rectangle out of each frame in PFS stream. You can either specify x and y coordinates of upper left and lower right corner (the coordinates start with 0 and rise in the left-to-right and up-to-botton directions) or give a combination of the options listed below. OPTIONS
--left <columns>, -l <columns> Number of columns to be cut out from the left edge of an image. --right <columns>, -r <columns> Number of columns to be cut out from the right edge of an image. --top <rows>, -t <rows> Number of rows to be cut out from the top edge of an image. --bottom <rows>, -b <rows> Number of rows to be cut out from the bottom edge of an image. --width <new_width>, -W <new_width> Width of an output image. Note that --width can be mixed with either --left or --right option. --height <new_height>, -H <new_height> Height of an output image. Note that --height can be mixed with either --top or --bottom option. --help, -h Print a list of commandline options. EXAMPLES
pfsin image.hdr | pfscut --left 20 --top 5 | pfsout out.hdr Cut out 20 columns from the left and 5 rows from the top edge of image.hdr and save frame as out.hdr. pfsin image.hdr | pfscut --left 20 --width 400 | pfsout out.hdr Cut out 20 columns from the left edge of image.hdr, and create output image 400 pixels in width. pfsin image.hdr | pfscut 0 0 511 511 | pfsout out.hdr Cut left-upper part of the image of the size 512x512 (note that coordinates start with 0 and 512 is the last row/column that is included in the resulting image). SEE ALSO pfsin(1) pfsout(1) BUGS
Please report bugs and comments to Dorota Zdrojewska <dzdrojewska@wi.ps.pl>. pfscut(1)