Good day! Is there a way on how to move all the files except for the last 10 (for example). Let's say, I have 150 files in a certain directory and I want to move only the first 140 files. I know that the solution for this particular specific example would be "head -140 | mv `xargs`", but the number of files are dynamic in number and changing. Therefore I want to think of something that logically move all the files except for the last 10.
How to do it?
I can't see your suggestion, can you re-post it? Thanks!
Hi birei,
I want NOT to move the last 10 files, the reason is that there might be a possibility the a certain application is doing something (e.g open for writing) on the last file (I have just set 10 for margin).
I mean that last 10 files seems arbitrary. It must be a better condition, like sorted by name, date or similar. I guess the modification time of the files because of the switches of your list command. I don't like to process files from output of a ls -l command, many probabilities of failing.
Your first command is ls -ltr. -t sorts by modification time, with newest first. -r reverses the order, so last 10 files will be the newest now.
With that I guess that those 10 files you would get with ls -ltr /home/user/logs/ | tail -10 will be the most recent you have modified. With this information, you could use another approach, for example, read modification time of every file, keep the ten most recent and move the rest, but I could be wrong or make the problem more difficult.
---------- Post updated at 16:35 ---------- Previous update was at 16:20 ----------
There is a command that list all files but last ten without additional complications:
And from there you can pipe to grep, awk, xargs, etc.
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