UNIX for Dummies Questions & Answers

Code:

awk '/01\/Aug/,/02\/Aug/ { print } ' input

Regards
Peasant.

Thanks, that helps.

However, would want to keep this open and await resolution using non-awk commands.

If I am not wrong then you are trying to extract lines between 01/Aug and 02/Aug.
For e.g. if it's like
abcd.....01/Aug a
1 2 3
4 5 6
abcds...02/Aug bc
you want an output like this
a
1 2 3
4 5 6
abcds...

In that case try below awk code it work's just fine
awk '
BEGIN {
print "Start of the PROGRAM"
mode=0
}
{
if (match($0,"01/Aug")) {
print (substr( $0,index($0,"01/Aug")+length("01/Aug")))
mode=1
}
else
if (match($0,"02-Aug")) {
print (substr($0,1,index($0,"02/Aug")-1))
mode=0
}
else
if (mode == 1)
print
}
END {
print "End of the PROGRAM"
}
' file1.txt

file1.txt is your input file.

Hi,

Well i wish to include "01/Aug" and "02/Aug" also in the output.

Also, I do not want to use awk as it fails at time when the input file is HUGE.

I am looking for alternatives to awk.

without awk it's tough to achieve what you are trying to do.
let me know if you find a solution

One way that should work is "sed".

However, not sure about the syntax.