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Getting error please help

 
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# 1  
Old 07-15-2011
Getting error please help
Hello Expert,

I have written this code please help me what i am doing worng...

Code:
while read eachline
do
VAL=$eachline| sed  -e 's/[^/]*$//' -e 's/default/default_new/'
cp -r $eachline $VAL
done < /user/oracle/Test_admin/myfolder/bakup/part_bkptemp_part_bkp_repeated/list.txt

while executing the above sh it give me below error...

Code:
Usage: cp [-fhipHILPU] [-r|-R] [-E{force|ignore|warn}] [--] src target
or: cp [-fhipHILPU] [-r|-R] [-E{force|ignore|warn}] [--] src1 ... srcN directory

Smilie
Last edited by radoulov; 07-15-2011 at 09:26 AM.. Reason: Code tags.
# 2  
Old 07-15-2011
I suppose you need something like this:
Code:
while read eachline
do

  VAL=$(
    printf '%s\n' "$eachline" | 
      sed  -e 's/[^/]*$//' -e 's/default/default_new/'
      )
    
  cp -r -- "$eachline" "$VAL"

done < /user/oracle/Test_admin/myfolder/bakup/part_bkptemp_part_bkp_repeated/list.txt

This User Gave Thanks to radoulov For This Post:
aks_1902
# 3  
Old 07-15-2011
Quote:
Originally Posted by radoulov
I suppose you need something like this:
Code:
while read eachline
do

  VAL=$(
    printf '%s\n' "$eachline" | 
      sed  -e 's/[^/]*$//' -e 's/default/default_new/'
      )
    
  cp -r -- "$eachline" "$VAL"

done < /user/oracle/Test_admin/myfolder/bakup/part_bkptemp_part_bkp_repeated/list.txt

---------- Post updated at 07:34 AM ---------- Previous update was at 07:33 AM ----------

AWESOME THANKS A MILLION
SmilieSmilie

---------- Post updated at 07:35 AM ---------- Previous update was at 07:34 AM ----------

it would be great if you can please explain what i was doing worng

Please
# 4  
Old 07-15-2011
The main error was in the following line:

Code:
VAL=$eachline| sed  -e 's/[^/]*$//' -e 's/default/default_new/'

In this case the assignment VAL=$eachline returns nothing but its return status,
so the rest of the code is meaningless: the cp gets two (or more, given you didn't quote the variables) arguments with the same value.

Something like this:

Code:
% for x in 1 2; do
v=$x | sed 's/1/2/'
echo cp $v $x
done
cp 1 1
cp 2 2


Thus you need command substitution: $( ... ).
 
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