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Splitting a file and sending results to another file

 
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# 1  
Old 09-21-2010
Splitting a file and sending results to another file
Hi

Here is my script:

Code:
 
#!/bin/bash
set -x
dir="/var/local/dsx/import"
gawk -F, '
 $1 == last1 && $2 == last2 {
  printf $0"\n" >> $dir/$2
 }
 $1 !=last1 || $2 != last2 {
  printf $0"\n" >> $dir/$2
 }
 {
  last1=$1
  last2=$2 
 } 
 '  $1

Here is my test file:

Code:
 
o,e,r
1,2,3
1,2,3
1,2,3
4,5,6
4,5,6
4,5,6
4,5,6
4,5,6
4,5,6

Basically I want to split my file and send the haf to another file, but I get this error:
Code:
gawk: cmd. line:5: (FILENAME=t FNR=1) fatal: division by zero attempted

Can somebody please help
# 2  
Old 09-21-2010
Code:
printf $0"\n" >> $dir/$2

Any script, language any paradigm unless the value that is divided is checked for zero, divide operation should not be attempted.
# 3  
Old 09-21-2010
You see, I'm re-directing to a path and filename variable
Code:
printf $0"\n" >> $dir/$2

Not a division as such
so
Code:
$dir=/var/local/dsx
$2=filename

# 4  
Old 09-21-2010
Quote:
Originally Posted by ladyAnne
You see, I'm re-directing to a path and filename variable
Code:
printf $0"\n" >> $dir/$2

Not a division as such
so
Code:
$dir=/var/local/dsx
$2=filename

My mistake, thanks for pointing it out.
Try this, its 0(2n) and not very efficient
Code:
cnt=`wc -l < inputfile`; awk -v var=$cnt '{ if ( NR <= (var/2) ) { print >> "one" } else { print >> "two" } }' inputfile

# 5  
Old 09-21-2010
Thanks, but I really need it to have this format .. simply because I have to build on it this way ..
Code:
#!/bin/bash
set -x
dir="/var/local/dsx/csv"
gawk -F, '
 $1 == last1 && $2 == last2 {
  printf $0"\n" > $dir/$2
 }
 $1 != last1 || $2 != last2 {
  printf $0"\n" >> $dir/$2
 }
 {
  last1=$1
  last2=$2 
 } 
 '  $1

I basically need to know how to pass the results to a directory and filename, but these have to be variables since I will be running the script on many different files, and the esults get stored in a seperate directory

---------- Post updated at 05:33 AM ---------- Previous update was at 05:11 AM ----------

Okay.. I see that the path is not recognized by gawk.. so I have kind of seperated it.
Code:
#!/bin/bash
set -x
dir="/var/local/dsx/csv"


gawk -F, '
	$1 == last1 && $2 == last2 { 
		printf $0"\n" '>> $dir/'$2
	}
	$1 != last1 || $2 != last2 {
		printf $0"\n" '>> $dir/'$2
	}
	{
		last1=$1
		last2=$2 
	}	
	'  $1

How do I redirect this output to a filname .. the filename comes from the data in the csv file

---------- Post updated at 05:34 AM ---------- Previous update was at 05:33 AM ----------

sorry, it should come from the filename of the sourcefile passed to it

---------- Post updated at 06:43 AM ---------- Previous update was at 05:34 AM ----------

Perhaps we can put it in a seperate awk script
# 6  
Old 09-21-2010
You can run the file and direct the output to a file, for example:

Code:
./yourfile > your_output_file

# 7  
Old 09-21-2010
The reason I want to do this within the scrpt, is because I have hundreds of files to run.. I eventually want it to run in a loop from my one directory of files, and store each output in another directory of resultant files
 
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