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while loop in /bin/sh

 
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# 1  
Old 03-11-2009
while loop in /bin/sh
Hi!

I want my script to enter in a while cicle. And I did a:

var=0

while [$var < 1]
do
echo "while"
done

this is very simple because it's just for testing

So what I think that was suppost to happen was
while
while
while
while
while
while
....
....
while

BUT nothing

what is wrong in my while

thanks
# 2  
Old 03-11-2009
Try changing the < operator:

Code:
while [ "$var" -lt 1 ]
do
  echo "while"
done

# 3  
Old 03-11-2009
Quote:
Originally Posted by radoulov
Try changing the < operator:

Code:
while [ "$var" -lt 1 ]
do
  echo "while"
done

thanks, it works but not in my script because it says line 29 [0: not found (????)
so my code is:


Quote:
#!/bin/sh

var=0
echo $var
LOGFILE=`mktemp -t svn_checkout.XXXXXX`
ICONPATH="`dirname $0`/svn.xpm"
list=`ssh ruben@192.168.1.3 "ls /esp-server/svn"`
URL=`zenity --entry --title="Subversion: Checkout" --text="$list

Enter repository folder according to the the aboves:" --entry-text="" --width=400 --window-icon="$ICONPATH" 2>&1`

if [ $? -eq 0 ] ; then
svn checkout svn+ssh://ruben@192.168.1.3/esp-server/svn/$URL &> $LOGFILE & pid1=$!
echo $pid1
zenity --progress --pulsate --auto-kill & pid2=$!
echo $pid2
DIR=/proc/$pid1
echo $DIR
while [$var -lt 1]
do
echo "while"
if [ -d $DIR ] ; then
echo "does exist"
else
echo "does not exist"
fi
done
rm -f $LOGFILE
fi
echo "end"
and my line 29 is the last fi. And I have a lot of echo to show me the status.
Now I realy don't know why it doesn't enter in the while
Can you help me??

thanks
# 4  
Old 03-11-2009
Change this:

Code:
[$var -lt 1]

to this

Code:
[ $var -lt 1 ]

You need a space after the opening bracket and another one before the closing one.
# 5  
Old 03-11-2009
Quote:
Originally Posted by radoulov
Change this:

Code:
[$var -lt 1]

to this

Code:
[ $var -lt 1 ]

You need a space after the opening bracket and another one before the closing one.

MANNNNNN no way. lol I lost sooooo many time and was just a space. lol

thanks
# 6  
Old 03-11-2009
other thing
here:
if [ -d $DIR ] ; then

how can I use a not
like -d $DIR but negative
# 7  
Old 03-11-2009
Code:
[ ! -d "$DIR" ]

or

Code:
[ -d "$DIR" ] || ...

 
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