Need to pull Yesterdays Date...


 
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Old 03-04-2009
Need to pull Yesterdays Date...

I tried this and it works for the most part, but if the date is 20090301, it displays 20090300.

YESTERDAY=$((`date +%Y%m%d` -1))
 
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DM_DATE(1)						User Contributed Perl Documentation						DM_DATE(1)

NAME
dm_date - print out the system date and time SYNOPSIS
This performs the same operation as the unix 'date' command, but using the Date::Manip module. dm_date [OPTION]... [+FORMAT] DESCRIPTION
This displays information about the current system time, or some other time. Options are: -h, --help Print online help. -d STRING, --date=STRING Display time described by STRING. STRING can be any string which can be parsed by Date::Manip. Please refer to the Date::Manip::Date documentation for details. -f DATEFILE, --file=DATEFILE This reads each line in DATEFILE, and extracts a date from it and prints out the information. Blank lines and lines starting with a pound (#) are ignored. Lines not containing a valid date are also ignored. -r FILE, --reference=FILE Displays the last modification time of FILE. -R, --rfc-2822 Displayc the date and time in RFC 2822 format. Example: Mon, 07 Aug 2006 12:34:56 -0600 -u, --utc, --universal Converts the date to UT (GMT) and prints out the information. Only one of -d, -f, or -r should be included. If more than one is included, the first one from the list (-d, -f, -r) is used and any other is ignored. The format string starts with a plus (+) and contains any of the format directives described in Date::Manip::Date. KNOWN BUGS
None known. BUGS AND QUESTIONS
Please refer to the Date::Manip::Problems documentation for information on submitting bug reports or questions to the author. SEE ALSO
Date::Manip::Date LICENSE
This script is free software; you can redistribute it and/or modify it under the same terms as Perl itself. AUTHOR
Sullivan Beck (sbeck@cpan.org) perl v5.16.3 2014-06-09 DM_DATE(1)