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awk to print filename words along with delimiter

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# 1  
Old 01-16-2018
awk to print filename words along with delimiter
Hi,
I have filename as:
Code:
010020001_S-FOR-Sort-SYEXC_20180109_062320_0100.x937

I need first 5 words of my filename along with the respective delimiters:
I tried this:

Code:
f=010020001_S-FOR-Sort-SYEXC_20180109_062320_0100.x937
echo $f | awk -F '[_-]' '{print $1$2$3$4$5}'
010020001SFORSortSYEXC

But i want output with delimiters like:
Code:
010020001_S-FOR-Sort-SYEXC

I dont want to add those delimiters in print manually because _,- is not fixed i may get all delimiters as _ or - or both.
Is there any way to print first 5 words of filename along with the delimiters?

TIA
# 2  
Old 01-16-2018
Hello gnnsprapa,

Could you please try following and do let me know if this helps you.
Code:
awk 'END{split(FILENAME, array,"_");print array[1] array[2]}' 010020001_S-FOR-Sort-SYEXC_20180109_062320_0100.x937

Thanks,
R. Singh
# 3  
Old 01-16-2018
thanks for suggesting the solution: I got this

Code:
010020001S-FOR-Sort-SYEXC

its missing the first underscore(_) between first 2 words of filename
# 4  
Old 01-16-2018
Hello gnnsprapa,

Apologies, in hurry I missed it. Please try following and let me know if this helps you.
Code:
awk 'END{split(FILENAME, array,"_");print array[1] "_"  array[2]}' 010020001_S-FOR-Sort-SYEXC_20180109_062320_0100.x937

Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
gnnsprapa
# 5  
Old 01-16-2018
Try also shell parameter expansion
Code:
echo ${f%[-_]${f#*[_-]*[-_]*[_-]*[_-]*[_-]*}}
010020001_S-FOR-Sort-SYEXC

This User Gave Thanks to RudiC For This Post:
gnnsprapa
# 6  
Old 01-16-2018
@RudiC
while trying this.i got output as
Code:
f=010020001_S-FOR-Sort-SYEXC_20180109_062320_0100.x937
echo ${f%[-_]${f#*[_-]*[-_]*[_-]*[_-]*[_-]*}}
010020001_S-FOR-Sort-SYEXC_20180109_062320_0100.x937

I dont want words after 5th word of filename .i.e i want only
Code:
010020001_S-FOR-Sort-SYEXC

@Ravinder
as i told i dont want to hardcore any delimiter, in your solution

Code:
awk 'END{split(FILENAME, array,"_");print array[1] "_"  array[2]}' 010020001_S-FOR-Sort-SYEXC_20180109_062320_0100.x937

i will get correct result but if my filename has "-" instaed of "_" then also it will give me "_" as i have hardcoded it:
for eg: i have 2 files as
Code:
f=010020001_S-FOR-Sort-SYEXC_20180109_062320_0100.x937
f1=010020001-S-FOR-Sort-SYEXC_20180109_062320_0100.x937

i want output as
Code:
010020001_S-FOR-Sort-SYEXC
010020001-S-FOR-Sort-SYEXC

appreciate your help so far, thanks
# 7  
Old 01-16-2018
What's your shell version? Does it offer "parameter expansion / Remove matching prefix/suffix pattern"?
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