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Grep for a line containing only 5 numbers

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# 1  
Old 12-04-2014
Grep for a line containing only 5 numbers
How would you grep for a line containing only 5 numbers? Something like this.

Code:
       10      2       12      1       13

# 2  
Old 12-04-2014
Hi Cokedude,

Question was not clear.
Could explain more precisely....

---------- Post updated at 06:54 AM ---------- Previous update was at 06:49 AM ----------

Try this

Code:
grep "10  2  12  1  13" filename

# 3  
Old 12-04-2014
Code:
awk 'NF==5 {for (i=1;i<=NF;i++) if ($i !~ /^[0-9]*$/) x=1; if (!x) print; x=""}' file

# 4  
Old 12-04-2014
Perhaps a bit more generic:
Code:
grep "[[:space:]]*10"[[:space:]]*2"[[:space:]]*12"[[:space:]]*1"[[:space:]]*13" file4
       10      2       12      1       13

# 5  
Old 02-25-2015
Code:
 echo "       10      2       12      1       13" | grep "^[ \t]*\d\+[ \t]*\d\+[ \t]*\d\+[ \t]*\d\+[ \t]*\d\+[ \t]*$"

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