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How to replace last 8 digits?

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# 8  
Old 06-21-2013
Quote:
Originally Posted by Fundix
How can you print the 5th column of that file using awk if there is no FS ?
Please dont hijak the thread. If you have any question start a new thread.
# 9  
Old 06-21-2013
Question was on Corona's example, and makes sense.
Answer: with FS="" it becomes the 5th position.
# 10  
Old 06-21-2013
Quote:
Originally Posted by vidyadhar85
Please dont hijak the thread. If you have any question start a new thread.
Dear vidyadhar85, i'm not hijacking anything, i'm here to share and learn Smilie

Let my try again.
Original file is :
Code:
19523479811841494432A2013052700000000
19523479811730333980A2013052700000000
19523479811417044397A2013052700000000
19523479811205895810C2013010120130131
A9523479811205895810A2013020120130228
19523479811205895810I2013030120130331
19523479811689774317A2013052700000000
19523479811659473312C2013050120130531
19523479811659473312C2013060120130630

That file has no FS, how can you retrieve field number 5 using awk ?
Code:
awk -F"" ' { print $5 } ' file

or
Code:
awk ' { print $5 } ' file

produce nothing

neither Corona's reply adding -F""
Code:
awk -F"" '{sub(/00000000$/, "22991231", $5); print}' file

if i use his original reply
Code:
awk '{sub(/00000000$/, "22991231", $5); print}' file > newfile

a diff between file and newfile display no difference.

So i hope you understand now my question

ps : i'm using and Aix 5.2.0 for my tests
Last edited by Fundix; 06-21-2013 at 03:34 AM.. Reason: notify platform
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