Hi,
I have a unix script which runs a process (informatica workflow). To trigger this workflow an entry is made into the crontab and it is scheduled to run.
Issue:
The crontab entry is commented out. But the process is running in the unix box and it was scheduled immediately. There is someone who is running the script manually and it is aborted immediately. The users in a particular group only will have access to do that. There is no change made to the cron tab entries, so there has to be some user who is triggering this process. Problem is ..if someone is triggering the process we cannot have another user doing it. How do i get the user account which triggers this process from the unix log. Is there any log file i could research to find the user id.
you do not need crontab entries to run scripts unless you just want them ... the user in question may be running the script directly on the command line or using at so there is no need to modify crontab ... also, the issue may be that it is running in a user's crontab so you may want to check the user crontab files for the entry ... i think your suspect is very likely running the script manually based on your description ...
if you need to restrict the script to one process only while it is running, modify your shell script to use a marker file or at least check for an existing PID of the process prior to continuing the script ... a search of the forums or google should show you how to do so ...
There are two different aspects here: finding out who had run the script and making sure no two instances of the script run simultaneously.
The first is probably impossible. I don't know of any Informatica log file which would tell you this and you probably have not system auditing turned on and configured appropriately to find it in the systems audit logs. You might consider configuring system auditing in the future if you are interested in such information.
Regarding the second problem: this is relatively easy. Change the script so that when it starts it writes a "PID-file". Classically these PID-files are stored in /var/run, are named like the command/process they belong to and contain the PID of the running job. The first thing this script should do is to check if such a PID-file exists. If it does, it aborts with some error, otherwise it creates the PID-file, does whatever it is supposed to do and deletes the PID-file upon exit. Here is a sketch for this:
Code:
#! /bin/ksh
typeset chProgName="$(basename $0)"
typeset -i iPID=$$
trap { \
rm -f /var/run/${chProgName}.pid \
} 0
if [ ! -r /var/run/${chProgName}.pid ] ; then
print - $iPID > /var/run/${chProgName}.pid
else
error_exit "Cannot proceed, another instance runs already"
fi
... normal code begins here ...
exit
just thinking about it further, if mailx works in your server, just have the script send you email as soon as it runs ... (mixing everybody's code) ...
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