UNIX for Advanced & Expert Users

Hi could someone help please,

The problem i have is that within a for loop in Unix scripting i want to loop a line seven times before it continues onto the next part of the script. I am struggling to come up with a way to get it to go round seven times. I was thinking of somehow using a counter, but i am not sure how yet. Can anybody else think of how i could make a specfic line loop the required amount of times.

Is there a reason you need to use a "for" loop? Give the "while" loop a try and use a counter as you have suggested.

Code:

for i in 0 1 2 3 4 5 6 7
do
  COUNT=0 
  while [ $COUNT -lt 7 ]
  do
    echo "Count is $COUNT"
    let COUNT+=$COUNT
  done
done

in ksh93 you can use a for loop to do the same thing:
for ((x=0; x < 7; x +=1))
do
  echo "Count is $x"
done

Hmm.. I use ksh, but if you're using csh, the repeat command may be what you want. "The repeat command re-executes the single subsequent command for count number of times."

Code:

% repeat 3 echo hi

hi
hi
hi