Hi there,
how can i print the first pattern occurrence in a .log file?

I want to print the filename of the first 17262?
I tried but all I can do is print all the lines with the number 17262?
I tried using awk and sed but nothing!
I just want filename!

Here´s an example:

17259 1349258032 773472 PS Some text
17262 1349258032 773735 CE Some text
17267 1349258052 351658 CS tests/filename Some text
17267 1349258052 352041 QS Some text
17259 1349258052 352109 QR Some text
17259 1349258052 352432 PS Some text
17267 1349258052 375328 CE Some text

I assume that you meant 17267 instead of 17262 .

awk '/^17267/{sub(/.*\//,"",$5);print $5;exit(0)}' file

Thanks but with

awk '/^17267/{sub(/.*\//,"",$5);print $5;exit(0)}' file

Or

awk -F/ '/^17267/{split($NF,a," ");print a[1];exit(0)}' file