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Ok, I am attempting to add a new program to startup during the runlevel 3. I am using Suse 10.
I made a script lets call it foostart and placed it in /etc/init.d. It has 777 permissions on the script. I then created a link ln -s /etc/init.d/foostart /etc/init.d/rc3.d/S99foostart But during bootup the script will not run. I can run /etc/init.d/footstart start and it will execute fine. I can even go into yast and see it in there and start it from there and it starts fine. What am I missing for it not to start during bootup. thanks for any help. |
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gold:/etc/init.d # ls -lrt /etc/init.d/foostart
-rwxrwxrwx 1 root root 143 2009-01-15 12:43 /etc/init.d/foostart gold:/etc/init.d # gold:/etc/init.d # ls -lrt /etc/init.d/rc3.d/S99* lrwxrwxrwx 1 root root 20 2009-01-15 12:50 /etc/init.d/rc3.d/S99foostart -> /etc/init.d/foostart gold:/etc/init.d # |
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Yes that's the right path, as there is no rc3.d and all other runlevel programs are in the paths.
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all looks fine for me so far... so this is a suse problem or something is wrong with the script itself... i've no suse system to test this. i've moved the thread to the suse subforum. maybe a suse user knows how to solve this?!
greets, DN2 |
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