Solaris

What are you saying? The timestamp being created is four hours ahead when you really need it four hours behind? Is that it?

The reference 4 hours old file was created in the /path/ as expected. i.e) four hours b4 from now.

but when u use the ls -l <timestamp file>

output is showing as created with sterday date and time. i.e oct 4th

Got it?

---------- Post updated at 04:48 AM ---------- Previous update was at 04:45 AM ----------


Also, please try this without the space between the bang and -newer.

getting the below error when I trying the above,

find: bad option !-newer
find: [-H | -L] path-list predicate-list

I think I understand.............

As I said previously, the find command is using the inode date/time, that is what is shown by

Code:

 
ls -l <timestamp file>

If that date/time is wrong then that explains why find is giving you the wrong output.

You need to test your timestamp creation script by running it and immediately looking at it with ls -l

The date/time shown needs to be four hours ago. If it is not, then your script is faulty. I can't see anything wrong with your script but others on this forum are expert coders and will tell you what's wrong, I'm sure of that.

Thanks!

/usr/bin/perl -le 'print scalar localtime (time() - 240*60);' - it is returning Thu Oct 4 23:17:59 2012

it is not correct.

I guess that's a little progress.

I'm not a Perl person so can't help with that.

Post if you fix it otherwise I'm sure others will chip in.

Your timestamp issues aside, since ls is always called with a single file argument, the -r and -t options have no effect. If you get the correct sort, it's because find happend to visit the files in that order.

Regards,
Alister

This should be better (while not perfect):

Code:

find /path/ -type f ! -newer 4_hours_older_file -exec ls -lrt {} +