sed command to print lines after expression


 
Thread Tools Search this Thread
Operating Systems Solaris sed command to print lines after expression
# 1  
Old 05-12-2010
sed command to print lines after expression

Hi guys.
I need a sed command to print like 10 lines after a regular expression is found in the log.

Can anyone help me out.

Thanks

---------- Post updated at 10:52 AM ---------- Previous update was at 10:34 AM ----------

never mind.
I just did the search bewteen two expressions.
# 2  
Old 05-12-2010
just in case you would need it later:

Code:
grep -n "$reg_exp" file.txt |while read LINE ;do i=$(echo $LINE |cut -d':' -f1 ) ;sed -n "$i,$(($i+10))p" file.txt ;done

Login or Register to Ask a Question

Previous Thread | Next Thread

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Grep command to search a regular expression in a line an only print the string after the match

Hello, one step in a shell script i am writing, involves Grep command to search a regular expression in a line an only print the string after the match an example line is below /logs/GRAS/LGT/applogs/lgt-2016-08-24/2016-08-24.8.log.zip:2016-08-24 19:12:48,602 ERROR... (9 Replies)
Discussion started by: Ramneekgupta91
9 Replies

2. Shell Programming and Scripting

Use sed to print first n lines and last n lines of an output.

Use sed to print first n lines and last n lines of an output. For example: n=10 Can it be done? Thanks. (7 Replies)
Discussion started by: carloszhang
7 Replies

3. Shell Programming and Scripting

sed print all lines between second and third identical lines

I am trying to extract a table of data (mysql query output) from a log file. I need to print everything below the header and not past the end of the table. I have spent many hours searching with little progress. I am matching the regexp +-\{99\} with no problem. I just can't figure out how to print... (5 Replies)
Discussion started by: godfreydanials
5 Replies

4. Shell Programming and Scripting

sed returns error "sed: -e expression #1, char 18: unterminated `s' command"

Hello All, I have something like below LDC100/rel/prod/libinactrl.a LAA2000/rel/prod/libinactrl.a I want to remove till first forward slash that is outputshould be as below rel/prod/libinactrl.a rel/prod/libinactrl.a How can I do that ??? (8 Replies)
Discussion started by: anand.shah
8 Replies

5. Shell Programming and Scripting

Would like to print 3 lines after a regular expression is found in the logfile

I would like to print 3 lines after a regular expression is found in the logfile. I'm using the following code: grep -n "$reg_exp" file.txt |while read LINE ;do i=$(echo $LINE |cut -d':' -f1 ) ;sed -n "$i,$(($i+3))p" file.txt ;done The above code things works fine,but sometimes gives erroneous... (3 Replies)
Discussion started by: joachimshaun
3 Replies

6. Shell Programming and Scripting

sed: -e expression #1, char 21: unterminated `s' command

I have read many threads, but I still didn't find the right answer. May be i didn't find the right thread, though are so many threads for the same question. Basically the situation is - find date in a file and replace it with another date. (its not homework, its part of lot of a big processing,... (10 Replies)
Discussion started by: avinthm
10 Replies

7. Shell Programming and Scripting

sed command : print lines having no # at the begining

I am trying to print those line which has no # in the begining of the line. The sed I used for this purpose as shown below is not giving the required output. echo 'PDE 5600' | sed -n 's/^\!#/&/p' Where lies the problem:confused: (3 Replies)
Discussion started by: hiten.r.chauhan
3 Replies

8. Shell Programming and Scripting

sed not printing lines before a regular expression.

Hey, I found a way to print the lines which is just before a regular expression, not including the expression. sed -n '/regexp/{n;p;}' myfile Now I'm looking for a way to print all lines, exept the regular expression and also the line before the same regular expression. Use code tags. (1 Reply)
Discussion started by: Livio
1 Replies

9. Shell Programming and Scripting

search for an expression in a file and print the 3 lines above it

Hi, I have a file like this comment.txt 1.img 2.img 3.img OK x.img y.img z.img not ok 1.img 2.img 3.img bad 1.img 2.img 3.img (7 Replies)
Discussion started by: avatar_007
7 Replies

10. Shell Programming and Scripting

SED printing just parts of lines that match an expression

Hi - I am guessing this is fairly simple for someone .. but I can not quite figure it out. I need a sed command to print just parts of lines from a file. e.g. filea.txt 4710451 : Success : MODIFY : cn=user1,dc=org,dc=uk Message log started Message log ended 4710452 : Success : MODIFY :... (7 Replies)
Discussion started by: sniper57
7 Replies
Login or Register to Ask a Question