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Operating Systems Solaris Unix scripting doubts
# 1  
Old 05-07-2010
Unix scripting doubts
i hav a file like this
Code:
-rwxr-xr-x   1 root     controlm    4141 Nov 13  2006 /opt/scripts/prod/fvaauditlos.ksh
-rwxr-xr-x   1 root     controlm    3958 Nov 13  2006 /opt/scripts/prod/fvaexpchbk1.ksh
-rwxr-xr-x   1 root     controlm    6471 Nov 13  2006 /opt/scripts/prod/fvaexpchbk2.ksh
-rwxr-xr-x   1 root     controlm    3960 Nov 13  2006 /opt/scripts/prod/fvaexpcrcm1.ksh

i want to print only below column, so plz suggest how to get this column alone
Code:
 root  
 root  
 root  
 root

Last edited by Scott; 05-07-2010 at 06:55 AM.. Reason: Please use code tags
# 2  
Old 05-07-2010
Code:
awk ' { print $3 } '  filename

This User Gave Thanks to amitranjansahu For This Post:
p_satyambabu
# 3  
Old 05-07-2010
Thanks Amit, i hav one more question, PLz calrify
i want print as below in 2 lines , plz tell me

Code:
root  /opt/scripts/prod/fvaauditlos.ksh
root  /opt/scripts/prod/fvaexpchbk1.ksh
root  /opt/scripts/prod/fvaexpchbk2.ksh
root  /opt/scripts/prod/fvaexpcrcm1.ksh

Last edited by Scott; 05-07-2010 at 06:55 AM.. Reason: Code tags, please...
# 4  
Old 05-07-2010
Code:
awk ' { print $3, $9 } '  filename

# 5  
Old 05-07-2010
Thanks Amit, i have one more question, plz calrify
i have a file lke this:

Code:
-rwxr-xr-x    1 oprvdw   controlm       4771 Mar  9 2009  vrc002093j.ksh
-rwxr-xr-x    1 oprvdw   controlm       4773 Mar  9 2009  vrc002092j.ksh
-rwxr-xr-x    1 oprvrc   controlm       5428 Apr  3 2009  vrc045016j.ksh
-rwxr-xr-x    1 oprvrc   controlm       5354 Apr  3 2009  vrc055141j.ksh
-rwxr-xr-x    1 svemietl controlm       2745 Feb 16 02:20 bdw0231185.sh
-rwxr-xr-x    1 svemietl controlm       2672 Feb 16 02:20 bdw0231145.sh

i want a script whcih gies o/p as below, plz tell me how t o write:

Code:
oprvdw :
vrc002093j.ksh
vrc002092j.ksh
oprvrc :
vrc045016j.ksh
vrc055141j.ksh
svemietl :
bdw0231185.sh
bdw0231145.sh

Last edited by Scott; 05-07-2010 at 06:56 AM.. Reason: Code tags, please...
# 6  
Old 05-07-2010
Code:
for i in $(awk '{print $3}' file | uniq)
do
  echo $i:
  grep " $i " file | awk '{print $9}'
done

This User Gave Thanks to jlliagre For This Post:
p_satyambabu
# 7  
Old 05-07-2010
Code:
 awk '{if ( $3 != name ){print $3 ; name=$3} print $9}' filename
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