Shell Programming and Scripting

Originally Posted by dinesh1985

input file
First Name - position from 1-5
Last Name- position 6-10
Age-Position 11-12
Say above is the format of input file.
Example:
DINESKUMAR21
SACHISHAH 23
23
GURUNTARIM22

In the above example,in the 3 rd record Name is missing. Now while reading the file line by line,I want to delete the 3 rd line during validation.

---------- Post updated at 08:47 AM ---------- Previous update was at 08:46 AM ----------

for the third line blankspaces will be present before 23

Originally Posted by pa.chidhambaram

...
You can use the below command to delete the invalid line.

cat data | awk '{ if(substr($1,1,5)!="" && substr($1,6,10)!="" && substr($1,11,12)!="") print $1}' > new_filtered_file_name.

Where the data is the input file.

...

Originally Posted by dinesh1985

Thanks for your replies ..i ll try it and update

---------- Post updated 06-26-09 at 03:20 AM ---------- Previous update was 06-25-09 at 03:54 AM ----------

I donot want to redirect to any new file. I want to delete the line from the file itself.
I have tried sed -i '3d' to delete the 3rd line. But my shell is not recognizing sed -i.

I have tried sed '3d' <filename> ..it is displaying the file without the 3rd line. But the 3rd line is not permanently deleted. Can anyone please help