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#1
01-25-2013
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To cut a string based on last index of identifier
here below is sample string Code:
null pointer dereference of 'resourceList' where null is returned from a method/opt/bld/fetch/ds/interzone/notification/LocalLineStatusNotificationListener.java:79 null pointer dereference of 'reList' where null is returned from a method/opt/bld/fetch/dunkindev6jbe4/src/com/ip/interzone/notification/LineStatusListener.java:45 i want to cut based on last index of '/' identifier. i tried Code:
cat fileName.txt | awk '.java' '{print $1}' | cut -d'/' f5but that would return only for partial since there are different number of '/' for each line.. so i need something to find last index of '/' and cut it and provide me only java file name |
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#2
01-25-2013
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This will get you the filename: Code:
sed -e 's#.*/##' -e 's/:.*//' inputfile Or simply use grep: Code:
grep -o [^/]*java inputfile Last edited by Subbeh; 01-25-2013 at 05:53 AM.. |
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#3
01-25-2013
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Code:
awk -F'[/:]' '{print $(NF-1)}' file |
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#4
01-25-2013
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Code:
awk '{gsub(/.*\/|:.*/,"")}1' file |
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