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pattern extract

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# 1  
Old 10-20-2008
pattern extract
Hi

I have a pattern like :
SYSTEM_NAME-232-S7-200810060949.LOG

Here I need to extract system name and the timestamp and also the numeric number after "-S" i.e 7 here .

I am not very sure of whether I should use sed / awk for this ?Smilie


Thanks,
Priya.
# 2  
Old 10-20-2008
I tried...
I am not good at doing cut cmd .
Tried some of the below cmds !

$ echo SYSTEM_NAME-232-S7-200810060949.LOG | cut -f3 -d"-"
S7
( i need 7 only)
$echo SYSTEM_NAME-232-S7-200810060949.LOG | cut -f1 -d"-"
SYSTEM_NAME
( i need SYSTEM_NAME-232 )


I am actually very confused .....Trying out variations but not that successful until now Smilie
# 3  
Old 10-20-2008
Use parameter expansion:
Code:
var=SYSTEM_NAME-232-S7-200810060949.LOG
echo ${var:17:1}
echo ${var%-*-*}

Last edited by danmero; 10-20-2008 at 10:39 AM.. Reason: remove sed solution
# 4  
Old 10-20-2008
Hammer & Screwdriver
Code:
> echo SYSTEM_NAME-232-S7-200810060949.LOG | cut -d"-" -f3 | cut -c2-
7
> echo SYSTEM_NAME-232-S7-200810060949.LOG | cut -c1-15
SYSTEM_NAME-232
> echo SYSTEM_NAME-232-S7-200810060949.LOG | cut -d"-" -f1-2         
SYSTEM_NAME-232

# 5  
Old 10-20-2008
Thanks for the reply ...
# 6  
Old 10-20-2008
What abt the timestamp ? I did the below

$echo SYSTEM_NAME-232-S7-200810060949.LOG | cut -d"-" -f 4|cut -d"." -f1

200810060949

but wondering that if this will be applicable if there is one less "-" in the string !?
Then it might give entirely different output!
# 7  
Old 10-20-2008
Code:
sed 's/.*\(20[0-9]\{10\}\).*/\1/'

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