Parsing X char from right to left


 
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# 1  
Old 10-17-2008
Parsing X char from right to left

I am new to bash scripts I need something quite easy to do in VBS,
When I wanted to get the first 5 chars I used funcition right(5,strGet)
how can I do the same in bash?
I am trying to get the MAC address in Ubuntu I have done so far

Code:
ifconfig wlan2 | grep HWaddr | awk '{print $5}' | sed -e 's/-/:/g'  >>/tmp/mac
output:
00:1F:1F:08:DD:WC:D0:X3:00:00:00:00:00:00:00:00
I need only(first 23 charcters):
00:1F:1F:08:DD:WC:D0:X3


thanks in advance,
4Script
Felipe Ferreira, Network System Administration
Nagios,Scripting,Security
# 2  
Old 10-17-2008
found MAC

well I just found out that the MAC address is also here
cat /sys/class/net/<INF>/device/net/<INF>/address
<INF> = interface ( eth0, wlan0) etc...
# 3  
Old 10-17-2008
use cut
Code:
cut -c 1-23

# 4  
Old 10-17-2008
No need to use grep or cut. Use the power of awk to simplify your script i.e.
Code:
ifconfig wlan2 | awk '/HWaddr/ { print substr($5,1,23) }'

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