my scripts does not check if directory exists


 
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# 1  
Old 09-23-2008
my scripts does not check if directory exists

Hello:

Can someone please help me figure out what is wrong here, my script does not move on to the "else" part even though there is no .ssh directory on my remote server:

$more putkey.sh
#!/bin/ksh

for server in `cat list`
do
if [ -d /.ssh ]; then
cat $HOME/.ssh/id_rsa.pub |ssh $server ' cat >> .ssh/authorized_keys && echo "key copied"'
else
cat $HOME/.ssh/id_rsa.pub |ssh $server ' mkdir .ssh && cat >> .ssh/authorized_keys && echo "key copied"'
fi
done


$./putkey.sh
Password:
sh: .ssh/authorized_keys: cannot create


The script works if the else part is executed:

$cat $HOME/.ssh/id_rsa.pub |ssh myserver ' mkdir .ssh && cat >> .ssh/authorized_keys && echo "key copied"'
Password:
key copied


Thanks.
# 2  
Old 09-23-2008
Are you trying to check if the /.ssh directory exists locally? Or are you trying to check if the /.ssh directory exists on the remote server?
# 3  
Old 09-23-2008
Quote:
Originally Posted by Sara-sh
..my script does not move on to the "else" part even though there is no .ssh directory on my remote server:
And what part of your script check if the directory exist on remote ?
# 4  
Old 09-23-2008
Maybe you need to check this:

Code:
ssh $server ls /$HOME/.ssh

If it returns
Code:
/$HOME/.ssh: No such file or directory

then do stuff
else do other stuff.
# 5  
Old 09-23-2008
I made a script a while back that does almost the same thing, but the usage is a little different,

"./ssh-putkey.sh -H server" is the most basic usage, but if you do a "-h", it will show you the complete usage.

I'm not real sure if Ksh has the getopts built-in for parsing command line options, as i wrote this for bash, but it should work.

Code:
#!/bin/bash

### defaults
ID_FILE="$HOME/.ssh/id_dsa"
username=$USER
rsa_or_dsa="dsa"

usage_line="$0 -H <host>\nOptions:\n\t-?|-h Display this Output\n\t-l <user>; Default == current user\n\t-f <identity file>; Default == '~/.ssh/id_dsa'\n\t-t <rsa|dsa> ***Only when generating new file; Default == $rsa_or_dsa"
### Start function
USAGE() {
        clear 
        echo -e "Usage: $usage_line"
        echo -e "\nIf you use the '-f' option,\n it will generate the file if it doesn't exist."
        echo -e "\nYou will have to enter the remote password once,\n ...but never again after that.\n"
        exit 2
                }
### End Function

### if no args, complain
[ "$#" -lt "1" ] && USAGE

### set command line options
while getopts ":f:t:H:l:?h" flag; do
        case $flag in
            f )  ID_FILE=$OPTARG ;;
            t ) rsa_or_dsa=$OPTARG ;;
            H ) remote_host=$OPTARG ;;
            l ) username=$OPTARG ;;
            ?|h )  USAGE ;;
        esac
done

### make sure options are set correctly, or complain
if [ -z $remote_host ]; then
        clear
        echo -e "\nYou need to specify a valid hostname or ip-address,\nof the remote host you want to connect to.\n"
        USAGE
        exit 1
elif [ $rsa_or_dsa != "rsa" -a $rsa_or_dsa != "dsa" ]; then
        clear
        echo -e "\nWhoa....the '-t' needs to be either 'rsa', or 'dsa'....not '$rsa_or_dsa', as you put it.\n\n"
        exit 1
fi

### make key files if not already there
[ -e "$ID_FILE" ] || ssh-keygen -t $rsa_or_dsa -f $ID_FILE || exit 1

### read pub file, and complain if it cant be read
pub_key=`cat $ID_FILE.pub`
[ -z "$pub_key" ] && (clear ; echo -e "$ID_FILE.pub could not be read...exiting.\n") && exit 1

### Start Function
SSH_PUT_KEY() {
        ssh $username@$remote_host "[ ! -d \$HOME/.ssh/ ] && mkdir \$HOME/.ssh/ ; echo $pub_key >> \$HOME/.ssh/authorized_keys"
                }
### End Function

### run function
SSH_PUT_KEY

It may look kinda big, and unfriendly, but it has never failed me, and it is very easy to use
, and it is commented so it shouldn't be that hard to modify it to suit your exact needs.

Have Fun!
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