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AWK in CSH script problems

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# 1  
Old 09-22-2008
AWK in CSH script problems
Hello Guys,

I was trying to obtain the information from the /etc/passwd file, here was my script:
Code:
38 echo -n "What's your login name? "
 39 set logname=$<
 40 echo "Your login name is $logname, your user's ID is `grep $logname /etc/passwd|awk -F: '{print $3}'`"
 41 echo " Your home dir is `grep $logname /etc/passwd |awk -F: '{print $6}'`"

But I can't get the right answer. The result is as follows:
Code:
echo -n What's your login name?
What's your login name? zhihua
set logname=zhihua
echo Your login name is zhihua, your user's ID is `grep zhihua /etc/passwd|awk -F: '{print }'`
grep zhihua /etc/passwd
awk -F: {print }
Your login name is zhihua, your user's ID is zhihua:x:1000:1000:Zhihua,,,:/home/zhihua:/bin/bash
echo  Your home dir is `grep zhihua /etc/passwd |awk -F: '{print }'`
grep zhihua /etc/passwd
awk -F: {print }
 Your home dir is zhihua:x:1000:1000:Zhihua,,,:/home/zhihua:/bin/bash

It seems that in the awk segment, the shell replaces inner awk's parameters $N with the shell script's variables.

How can i avoid this problem? Thanks in advance!!
# 2  
Old 09-22-2008
As I tried many times, and now I have a fix: Do NOT use the double quotes around the awk command in echo
Code:
echo "Your login name is $logname, your user's ID is " `grep $logname /etc/passwd|awk -F: '{print $3}'`
echo "Your home dir is " `grep $logname passwd |awk -F: '{print $6}'`

If I add the double quotes around the awk, the csh interprets the $3 or $6 as the shell variables. And I still don't get it. Anyone knows please shed some light on this.
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