Shell Programming and Scripting

i have a file as:

1
2
3
4
5

i want output as :

1 2 3 4 5

can anybody help on this??

Try this:

Code:

cat filename | xargs

Some thing similar
+++++++
cat filename | paste -s -
+++++++
Or for more advance operations, I have awk script by some forum like this
+++++++
#! /bin/sh

## ------------------------------------------------------------
## -- Transpose a matrix:
## -- Assumes all lines have same number of fields
## --
## -- Usage:
## -- script <STDIN> ^D
## -- script <input file>
## -- cat <input file> | script
## ------------------------------------------------------------
exec awk '
BEGIN {
FS = ","
OFS = ","
}
NR == 1 {
n = NF
for (i = 1; i <= NF; i++)
row[i] = $i
next
}
{
if (NF > n)
n = NF
for (i = 1; i <= NF; i++)
row[i] = row[i] "," $i
}
END {
for (i = 1; i <= n; i++)
print row[i]
}' ${1+"$@"}
+++++++
This assumes "," as input file field seperator

Why are you using cat?

Code:

xargs < filename

thnx a lot for ur nice suggestions ......

Or:

Code:

echo $(<filename)

Code:

$ printf "%s\n" 1 2 3 4 5 > filename
$ echo $(<filename)

$ echo $(cat < filename)
1 2 3 4 5
$

When posting non-standard solutions, please specify which shell you are using.