Shell Programming and Scripting

Actually you could change this to

Code:

{ for (l in r) {
  if ((c[l] == "." && $0 ~ r[l]) || (t = tolower ($0) && t ~ tolower(r[l]) && t ~ tolower(c[l]))) {
    ++n[l]
  }
}

That's pretty ugly and ad-hoc, but implements case-insensitive matching when there are two regular expressions, i.e. the "check2" case. (Actually the tolower(r[l]) and tolower(c[l]) should happen already in the first loop, optimally.)

you can check grep with -l option or -m 1 option

like

Code:

somevariable=`grep -l "searchstring" filename`

The above command will return a filename if any search pattern found.it will terminate after finding first match in the file and hence save time.you can check if "somevariable" is zero byte then not found.
or

Code:

somevariable=`grep -m 1 "searchstring" filename`

The above command will return a line where pattern found.it will terminate after finding first match in the file and hence save time.you can check if "somevariable" is zero byte then not found.

Dhruva: if the task is to count the number of occurrences, you obviously can't stop early.

I agree if the task is to count number of occurrences, we can't stop early.I assumed and suggested if he do not need count and he is using count for the sake of test condition then this can be the way to try for.

Can you please help us to figure out why this is happening?