Shell Programming and Scripting

hello all
i need help to print text between -L and \myproject using bash shell command on following text. i am using sed to do but not get success. i want to print only C:\Users\myname\workspace\. how can i do?

g++ -L"C:\Users\myname\workspace\myproject\lib\ffgeneralutil\lib" -L"C:\Users\myname\workspace\myproject\lib\ffsockwrapper\lib" -L"C:\Users\myname\workspace\myproject\MessageHandler\MsgLib\MtContainer\lib" -L"C:\Users\myname\workspace\myproject\lib\ffrs232\lib" -L"C:\Users\myname\workspace\myproject\lib\ffthread\lib" -L"C:\Users\myname\workspace\myproject\lib\md5wrapper\lib" -L"C:\Users\myname\workspace\myproject\lib\fflogger\lib" -L"C:\Users\myname\workspace\myproject\MessageHandler\MsgLib\LzoMessageCompression\lib" -L"C:\Users\myname\workspace\myproject\MessageHandler\MsgLib\MsgIntegrityUtil\lib" -L"C:\Users\myname\workspace\myproject\MessageHandler\MsgLib\MoContainer\lib" -o"myproject" $(OBJS) $(USER_OBJS) $(LIBS)
@echo 'Finished building target: $@'
@echo ' '
# Other Targets
clean:
-$(RM) $(OBJS)$(C++_DEPS)$(C_DEPS)$(CC_DEPS)$(CPP_DEPS)$(EXECUTABLES)$(CXX_DEPS)$(C_UPPER_DEPS) myproject
-@echo ' '

Code:

sed 's/-L"\(.*\)mypro.*/\1/'

If this isn't what you mean, clarify your question.

Regards

no it is not helping. i need only "C:\Users\myname\workspace", part but is printing the whole paragraph. i only want to print above line. dosent matter how many times come in the file. hope i explained the point.

BR
shailesh

Try this variation:

Code:

sed -n 's/.*-L"\([^ ]*\)\\mypro.*/\1/p'

now it is not printing anything
br
shailesh

I copied and pasted your sample text above into a file called t and ran it, and this is the output I get:

Code:

$ sed -n 's/.*-L"\([^ ]*\)\\mypro.*/\1/p' t
C:\Users\myname\workspace
$

What version of sed are you using, and under what OS?

my OS is open SUSE 10.3 and sed version is "GNU sed version 4.1.5". surprised why it is not working. i did the same on my machine and nothing comes out.
BR
shailesh