Shell Programming and Scripting

Hello guys, i need your help, let me try to explain what i need:

I have a file (plain text) for example with 500 lines, i need to read only from the line 200 until the end of file, and serch the word 'ERROR' onli between lines 200 and 500, that have sence?

Thanx for your help.

We understand what you need, however can you post what you have tried so far and to let us see where you're at and we'll see how we can assist.

A quick solution is
sed -n '200,$p' file | grep ERROR
Thanks,
CSS

@sudhamacs check the OP request.

Thanx sudhamacs , however, i need to set the start line (in this case 200) by paramether, i mean, i have the number of line to start my search in a variabla names LINEA, but there is an error if i try:

sed -n '$LINEA,$p' file | grep ERROR

if you need to use variable then use double quotes instead of single quote for the value of the variable to effect.

sed -n "$LINEA,$ p" file | grep ERROR

Also note that there is a space between $ and p.
$ means the end of the file
p means print

if you don't want to search till end of the file, i.e. you want to search till line 500 then you can replace $ with 500, or with a variable.

Thanks,
CSS

I don't think that sed + grep is the right direction, anyway awk can sed and grep. What about:

Code:

awk 'NR >= "'"$LINEA"'" && NR <= "'"$LINEB"'" && /ERROR/' data.file