Shell Programming and Scripting

Hello fpmurphy,

It helps me lot, appreciated your assistence.
I was trying to modify my requirement, everything went fine except one confusion:

If the text file contains as follows:

./s/sherg_fyd_rur:blkabl="R23.21_BL2008_0122_1"
./h/serge_a75:rlwual="/main/r23.21=26-Mar-2008.05:00:20UTC@R11.31_BL2008_0325"
./y/serge_a75:blkabl="R23.21_BL2008_0325"
./w/sherg_proto_npiv:bkguals="R23.21_BL2008_0302 I80_11.31_LR"

Then I modified the command as follows:

"Stage 1"
sed -e 's/\(^\.\/.*\)//'

It's appearing parse error.

I wanted to replace like ./s/ and I put additional .*, but not working.
Any idea?

Thank you.

abrouf

Little modification:
I tried as follows:

Then I modified the command as follows:

"Stage 1"
sed -e 's/\(^\.\/.*/\)//'

to replace like ./s/ or ./h/

Thank you.
abrouf

Hello fpmurphy,

Please help! I also tried making the 6 splits. Put the additional characters s/ or h/ into another veriable, but still showing parse error and returning the out put to \3 \5.

Please help.
Thank you.
abrouf

it seems you have a standard structure,

Code:

awk 'BEGIN{
 FS="[.=@: /\"]"
}
/\.\//{
 print $3
 for ( i=2;i<=NF;i++){
  if ( $i ~ /BL/) {
    sub(/.*BL/,"",$i)
    print $i
  }
 }
} 
' file

output:

Code:

# ./test.sh
sherg_fyd_rur
2008_0122_1
serge_a75
2008_0325
serge_a75
2008_0325
sherg_proto_npiv
2008_0302

if you are not familiar with regular expression, then use less of it , until you do.

Thank you ghostdog74,

Actually my file content is as follows:
./s/sherg_fyd_rur:blkabl="R23.21_BL2008_0122_1"
./h/serge_a75:rlwual="/main/r23.21=26-Mar-2008.05:00:20UTC@R11.31_BL2008_0325"
./y/serge_a75:blkabl="R23.21_BL2008_0325"
./w/sherg_proto_npiv:bkguals="R23.21_BL2008_0302 I80_11.31_LR"

The previous sed command works file, I wanted to replace
./s/
./h/
./y/
./w/

So I modified as
sed -e 's/\(^\.\/.*/\)//'

added .*/ to replace like s/, but this part is not working. I also put this part different pattern buffer, still no luck.

I appreciate your help.

Thank you.

abrouf