Shell Programming and Scripting

Hello

Its a simple issue i suppose.I am trying to write a script which first logson to other server via SSH & tries to stop a process ,then returns to its originator & completes a task & finally jumps to that second servers again & starts the (stopped) process.

What i am not able to implement is after logging on to the second server via SSH,it does not execute script logic but waits on command prompt for user input.
If i say 'exit' ,it returns to the originator & resumes script execution.

I am pasting the script here( part of it )

echo "--------------------------------"
echo "Connecting to node controller on <server 2>.....please wait"
ssh <username>@<server 2>
sleep 5
echo "--------------------------------"
b=server2
a=`uname -n`
if [ $a -eq $b ]
then
echo "----------------------------"
echo "Connected to server2 successfully"
echo "----------------------------"
fi
sleep 5
echo "Stopping node controller on <server 2>.....please wait"
cd <install_root>/bin
. ./setupenv.sh
echo "---------------------------------"
sleep 5
#echo "Stopping the node controller...please wait"
./nctrl stop

Here is a problem:
It logson to server 2 correctly but just waits at the command prompt.


Please help me in finding the flaws with the script.

Regards
Abhi

Are you sure that the output of $a and $b are the same ? Add -x flag at the shebang line and debug it. Can you execute all those commands from the prompt, without using the script ?

If you use this command, it will execute the command on the remote end:

However, if you pipe the output through to another command, THAT PART will be processed locally, and the outputfile will also be in the local directory, like this:

You put the SSH-statement on a single line, which indeed will wait for your input and hold execution of the remaining script, until you exit the SSH-session.