grep for pattern


 
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# 1  
Old 05-08-2008
grep for pattern

hi

i hav a file containing the values as

RTMS_LOCATION_CDR PERIODIC_LOCATION_REPORT 1210241292536501rtmssrv1 20080508153812394 395 396 INTERNAL 1406 GMLC919440000857 SUCCESS0 1210241288197338
RTMS_LOCATION_CDR PERIODIC_LOCATION_REPORT 1210241292536501rtmssrv1 20080508153812394 395 396 INTERNAL 1409 GMLC919490242288 SUCCESS0 1210241288197338
RTMS_LOCATION_CDR PERIODIC_LOCATION_REPORT 1210241299342509rtmssrv1 2008050815381966 258 261 INTERNAL 928 GMLC919444395566 SUCCESS0 1210241288921341
RTMS_LOCATION_CDR PERIODIC_LOCATION_REPORT 1210241310313520rtmssrv1 20080508153830394 395 396 INTERNAL 1410 GMLC919440000808 FAILURE1 1210241310267368
RTMS_LOCATION_CDR PERIODIC_LOCATION_REPORT 1210241317531525rtmssrv1 2008050815383966 255 256 INTERNAL 910 GMLC919444395454 SUCCESS0 1210241314898375
RTMS_LOCATION_CDR PERIODIC_LOCATION_REPORT 1210241317531525rtmssrv1 2008050815383966 255 256 INTERNAL 903 GMLC919444395462 SUCCESS0 1210241314898375
RTMS_LOCATION_CDR PERIODIC_LOCATION_REPORT 1210241317531525rtmssrv1 2008050815383966 255 256 INTERNAL 907 GMLC919444395471 SUCCESS0 1210241314898375
RTMS_LOCATION_CDR PERIODIC_LOCATION_REPORT 1210241317531525rtmssrv1 2008050815383966 255 256 INTERNAL 904 GMLC919444395480 SUCCESS0 1210241314898375
RTMS_LOCATION_CDR PERIODIC_LOCATION_REPORT 1210241317531525rtmssrv1 2008050815383966 255 256 INTERNAL 908 GMLC919444395452 SUCCESS0 1210241314898375


i need to grep for all the records having column nos 106,107,108 as 255

can any one help me out
# 2  
Old 05-08-2008
Use cut, then grep
# 3  
Old 05-08-2008
awk '$5==255 || $5==106 || $5==107 || $5==108 {print $0}' filename

Thanks
penchal
# 4  
Old 05-08-2008
Code:
awk ' 
          $5 ~ /^10[6-8]/  { print $0 ; next }
          $5 ~ /^255/ { print $0 ; next }'

# 5  
Old 05-08-2008
Quote:
Originally Posted by penchal_boddu
awk '$5==255 || $5==106 || $5==107 || $5==108 {print $0}' filename

Thanks
penchal
hi penchal,

great ...u hav given me the way to find the answer. If u dont mind can u explain whatever u hav given
# 6  
Old 05-08-2008
Hi,

awk splits the input lines into fields with space as delimiter.

For your first line of file,

$1=RTMS_LOCATION_CDR
$2=PERIODIC_LOCATION_REPORT
.
.
$5=392
..
.
$11=1210241314898375

In awk script, Place a condition on the 5th filed.
If condition is satisfiled print that entire line

Thanks
Penchal
# 7  
Old 05-08-2008
hi ....can u pls explain the command
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